All categories

2 years ago

Which angles could form an obtuse triangle?

Mathematics

2 answers:

Afina-wow [57]2 years ago

8 0

The answer is c because an obtuse triangle is over 90 degrees and 112 is over 90

uranmaximum [27]2 years ago

5 0

Answer:

C. because it is the only set with an angle over 90 degrees like the angle is obese (to remember)

Step-by-step explanation:

You might be interested in

Triangles 1 and 2 are both isosceles. They each have a 30 degree angle. Explain why these triangles don't have to be similar to

Vladimir79 [104]

Step-by-step explanation:

Triangle 1 can have 30°, 75° and 75° angles whereas Triangle 2 can have 30°, 30° and 120° angles.

Since they do not have all 3 congruent angles, they are not similar.

8 0

2 years ago

It’s x+8 at the bottom but if you solve this please give me a step by step so I know how to solve it, thank you!!♥️

OLga [1]

Answer:

x=4.

Step-by-step explanation:

Let's solve your equation step-by-step.

5/15=x/ x+8

Step 1: Cross-multiply.

5/15=x/ x+8

5*(x+8)=x*(15)

5x+40=15x

Step 2: Subtract 15x from both sides.

5x+40−15x=15x−15x

−10x+40=0

Step 3: Subtract 40 from both sides.

−10x+40−40=0−40

−10x=−40

Step 4: Divide both sides by -10.

−10x−10=−40−10

Then your answer will be x=4.

6 0

2 years ago

Whats 69x420?????????

IRISSAK [1]

Answer:

28980

Step-by-step explanation:

Also "<em>nice</em>"

3 0

3 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

2 years ago

Read 2 more answers

Write the sentence as an equation.41 fewer than the quantity t times 307 is equal to n

Serhud [2]

The given statement is:

41 fewer than the quantity t times 307 is equal to n.

The equation is given by:

$307t-41=n$

3 0

1 year ago