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emmainna [20.7K]
3 years ago
12

I need help,,,,,,,,,,

Mathematics
2 answers:
Brrunno [24]3 years ago
5 0

Answer:

Gina went the farthest and Greg went the least distance

Step-by-step explanation:

6/6 > 4/6 > 3/6

kow [346]3 years ago
5 0
Gina = Longest



Greg = Shortest
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The diagonals of a rhombus have lengths of 12 centimeters and 16 centimeters. what is the length of one side of the rhombus
Yuki888 [10]
<span>Diagonals of a rhombus are perpendicular and bisect each other. This means this rhombus is composed of four right triangles with legs of length 6 cm and 8 cm, with their hypotenuses forming the perimeter of the rhombus. The Pythagorean theorem a^2+ b^2 = c^2 can be used to find the length of the hypotenuse. 6^2+8^2 = 36+64 = 100. The square root of 100 is 10, so the length of a side of the rhombus is 10 cm.</span>
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3 years ago
−7/8 −(−5/6) ​ in simplest form
svp [43]

Answer:

-1/24

Step-by-step explanation:

-7/8 - (-5/6)

Subtracting a negative is like adding

-7/8 + 5/6

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-42/48 + 40/46

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3 0
3 years ago
How can you write a percent as an equivalent fraction?
erik [133]

Answer:

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Step-by-step explanation:

I hope this helps

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PLEASE HELP ASAP 25 PTS TO RIGHT/BEST ANSWER
Novay_Z [31]
Subtract 1111 from both sides

5{e}^{{4}^{x}}=22-115e​4​x​​​​=22−11


 

Simplify 22-1122−11 to 1111

5{e}^{{4}^{x}}=115e​4​x​​​​=11



 

Divide both sides by 55

{e}^{{4}^{x}}=\frac{11}{5}e​4​x​​​​=​5​​11​​



 

Use Definition of Natural Logarithm: {e}^{y}=xe​y​​=x if and only if \ln{x}=ylnx=y

{4}^{x}=\ln{\frac{11}{5}}4​x​​=ln​5​​11​​



 

: {b}^{a}=xb​a​​=x if and only if log_b(x)=alog​b​​(x)=a

x=\log_{4}{\ln{\frac{11}{5}}}x=log​4​​ln​5​​11​​



 

Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}log​b​​x=​log​a​​b​​log​a​​x​​

x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=​log4​​logln​5​​11​​​​



 

Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}log​b​​x​c​​=clog​b​​x
\log{4}log4 -> \log{{2}^{2}}log2​2​​ -> 2\log{2}2log2

x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=​2log2​


Answer= −0.171
7 0
3 years ago
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