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ryzh [129]
3 years ago
12

Find the area of an octagon with a side length of 6

Mathematics
2 answers:
miskamm [114]3 years ago
6 0

Answer:

173.82 cm^2 to the nearest hundredth.

Step-by-step explanation:

We can split it up into 8 isosceles triangles of equal area.

The base of one of these triangles = 5 cm in length.

The vertex angle is 360 / 8 = 45 degrees.

We can draw a perpendicular line from the center to form  2 right angled triangles and the 45 degree angle is split into 2 angles of 22.5 degrees and the base of these triangles is 1/2 * 6 = 3 cm.

The height of an isosceles triangle is found as follows:

tan 22.5 = 3 / h

h = 3 / tan 22.5

So the area of the isosceles triangle =   (3 * 3 / tan 22.5) cm^2.

Total area of the octagon = 8 * 3 * 3 / tan 22.5

= 173.82 cm^2.

Reika [66]3 years ago
4 0

Area = 2(1+sqrt(2))(sidelength^2)

A = 173.82

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