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3 years ago

What is the equation of a line that is parallel to x=−5 and that passes through the point (1,4)

1 answer:

8 0

Answer: x = 1

The given line x = -5 is a vertical line through -5 on the x axis. Every point on this line has an x coordinate of -5. Similarly, the line x = 1 has all of its points with x coordinate of 1. One of those points is (1,4). Any vertical line has an undefined slope. Any two vertical lines are parallel to one another.

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Identify the first five terms of the sequence in which a1 = 5 and an = 2an−1−3 for n ≥ 2.

ziro4ka [17]

Answer:

5, 7, 11, 19, 35

Step-by-step explanation:

Using the recursive formula and a₁ = 5 , then

a₂ = 2a₁ - 3 = (2 × 5) - 3 = 10 - 3 = 7

a₃ = 2a₂ - 3 = (2 × 7) - 3 = 14 - 3 = 11

a₄ = 2a₃ - 3 = (2 × 11) - 3 = 22 - 3 = 19

a₅ = 2a₄ - 3 = (2 × 19) - 3 = 38 - 3 = 35

Thus the first 5 terms are

5, 7, 11, 19, 35

3 0

3 years ago

Is the square root of 100 a terminating or repeating decimal

den301095 [7]

the answer is terminating

5 0

3 years ago

Read 2 more answers

Let |u| = 10 at an angle of 45° and |v| = 13 at an angle of 150°, and w = u + v. What is the magnitude and direction angle of w?

mixer [17]

Given:

$|u|=10$ at an angle of 45°.

$|v|=13$ at an angle of 150°.

$w=u+v$

To find:

Magnitude and direction angle of w.

Solution:

We have,

$w=u+v$

$\theta = 45^\circ, \phi = 150^\circ$

Now,

$u_x=|u|\cos \theta=10\cos 45^\circ=7.071$

$u_y=|u|\sin \theta=u_y=10\sin 45^\circ=7.071$

$v_x=|v|\cos \phi=13\cos 150^\circ=-11.25833$

$v_y=|v|\sin \phi=u_y=13\sin 150^\circ=6.5$

Using these information, we get

$R_x=u_x+v_x=7.071-11.25833=-4.18733$

$R_y=u_y+v_y=7.071+6.5=13.571$

$\text{Direction angle}=\tan^{-1}(\dfrac{R_y}{R_x})$

$\text{Direction angle}=\tan^{-1}(\dfrac{13.571}{-4.18733})$

$\text{Direction angle}=-72.8239$

$\text{Direction angle}=107.1476$

$\text{Direction angle}\approx 107.1$

Now,

$|w|=\sqrt{(|u|\cos \theta +|v|\cos \phi)^2+(|u|\sin \theta +|v|\sin \phi)^2}$

$|w|=\sqrt{(10\cos(45)+13\cos 150)^2+(10\sin(45)+13\sin 150)^2}$

$|w|=\sqrt{(10(\dfrac{1}{\sqrt{2}})+13(-\dfrac{\sqrt{3}}{2}))^2+(10(\dfrac{1}{\sqrt{2}})+13(\dfrac{1}{2}))^2}$

$|w|=14.20236$

$|w|\approx 14.20236$

Therefore, the correct option is D.

4 0

3 years ago

Read 2 more answers

29 mm 가 120 mm D What is the perimeter? millimeters

Stella [2.4K]

Pythagoras theorem : a^2 + b^2 = c^2

20^2 + b^2 = 29^2

400 + b^2 = 841

841 - 400 = 441

Square root 441 = 21

PERIMETER :

21+29+20 = 70

The answer is 70

7 0

3 years ago

number that can be divided evenly by only itself and by the number 1 is called which of the following? Prime Variable Prime Term

Ivenika [448]

The answer is Prime Factor.

8 0

3 years ago