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2 years ago

Which is not a factor of 60? A.4 B.8 C.12 D.15

Mathematics

2 answers:

konstantin123 [22]2 years ago

8 0

Step-by-step explanation:

A. 60/4 = 15

B. 60/8 = 7.5

C. 60/12 = 5

D. 60/15 = 4

So, the answer to this is B, 8.

Hope this helped!!

~A̷l̷i̷s̷h̷e̷a̷♡

nordsb [41]2 years ago

5 0

Answer:

Step-by-step explanation:

you could draw a factor tree and list out the factors, however you would not see 8 as an factor

hope this helps!

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Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ

Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

$f(x)=(x-3)^{-2}$

When we differentiate this function with respect to x, we get;

$f'(x)=-\frac{2}{(x-3)^3}$

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

$0.06-0.25=-\frac{2}{(c-3)^3} (6)$

$-0.19=-\frac{12}{(c-3)^3}$

$(c-3)^3=\frac{-12}{-0.19}$

$(c-3)^3=63.15789$

$c-3=\sqrt[3]{63.15789}$

$c=3+\sqrt[3]{63.15789}$

$c=6.98$

If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

3 0

3 years ago

To join the meeting vyv-vmvx-qnp

zmey [24]

Answer: yk i just a flight away if u wanna u can take a private plane

Step-by-step explanation:

Telepathia

3 0

3 years ago

Anuta_ua [19.1K]

Lets say you have 5 apples, but the you give away 3 of them.
To work how many you have left you take away.
5-3 = 2

Lets apply this with fractions now.
You have 9/7 yard, but then you give away 7/20 yard.
Now you take them away:
9/7 minus 7/20 = 131/140

Hope this helps :)
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8 0

3 years ago

What is the inverse function f(x)=-3x-2

vesna_86 [32]

f^-1 (x) = 2/3 + x/3

6 0

2 years ago

Determine whether the statements are True or False. Justify your answer with an explanation.

frez [133]

Problem 1

<h3>Answer: False</h3>

---------------------------------

Explanation:

The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.

So,

f(x) = x+1

f( g(x) ) = g(x) + 1 .... replace every x with g(x)

f( g(x) ) = 6x+1 ... plug in g(x) = 6x

(f o g)(x) = 6x+1

Now let's flip things around

g(x) = 6x

g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)

g( f(x) ) = 6(x+1) .... plug in f(x) = x+1

g( f(x) ) = 6x+6

(g o f)(x) = 6x+6

This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.

===============================================

Problem 2

<h3>Answer: True</h3>

---------------------------------

Explanation:

Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.

For example, let

f(x) = 1/(x+2)

g(x) = -2

The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.

So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).

7 0

3 years ago