Solution
-3b + 11 = -18 + 8b
-3b - 8b = -18 - 11
-11b = -29
b = 29/11
The value of f(a)=4-2a+6
, f(a+h) is 
, [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6
.
Given a function f(x)=4-2x+6.
We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.
Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.
f(a)=4-2a+6 (By just putting x=a).
f(a+h)==
=4-2a-2h+6(
)
=4-2a-2h+6
=
[f(a+h)-f(a)]/h=[-(4-2a+6 )]/h
=
=
=6h+12a-2.
Hence the value of function f(a)=4-2a+6, f(a+h) is , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6.
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The answer is a. $35. First you multiply 25 by .40. Then you add the product to 25.
(-1,-2) and (-1,4)
so these have same x values, but different y values, so these are on differnt sidef of circle
distanc between them is 6
6/2=3
radius=3
so move 3 units up from (-1,-2)
(-1,1)
so
if center is (h,k) and radius is r then
(x-h)^2+(y-k)^2=r^2
(-1,1) is center and r=3
(x-(-1))^2+(y-1)^2=3^2
(x+1)^2+(y-1)^2=9
So
bowl is a half sphere
cylinder is a cylninder
cone is cone
bowl:
area of circle=4/3 pi times r^3
half bowl=4/3 times 1/2 times pi times r^3=2/3pi r^3
cylinder=height times pi times radius^2
this cylinder=r times pi times r^2=pi times r^3
cone=1/3 times height times pi times radius^2
thgis cone=1/3 times r tiimes pi times r^2=1/3 times pi times r^3
compare
bowl=2/3 pi r^3
cylinder=pi r^3
cone=1/3 pi r^3
the cylinder is biggest
CYLINDER IS THE ANSWER
2.
sphwere=4/3 times radius^3 times pi
this sphere=4/3 times pi times r^3
cylinder=height times radius^2 time pi
this cylinder=2r times r^2 times pi=2r^3 times pi
cone=1/3 times height time r^2 times pi
this cone=1/3 times 2r times r^2 times pi=1/3 times 2r^3 times pi=2/3 times r^3 times pi
sphere:4/3 pi r^3
cylinder: 2 pi r^3
cone: 2/3 pi r^3
