The correct answer is: [D]: " <span>x-int : 1 , y-int: 0.5 " .
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Note:
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The "x-intercept" refers to the point(s) at which the the graph of a function (which is a "line", in this case) cross(es) the "y-axis".
In other words, what is (are) the point(s) of the graph at which "x = 0<span>" ?
</span>
By examining the graph, we see that when " x = 0" ; y is equal to: "1<span>" .
</span>
So; the "x-intercept" is at point: "(0, 1)" ; or, we can simply say that the
"x-intercept" is: "1" .
_________________________________________________________</span> Note:
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The "y-intercept" refers to the point(s) at which the the graph of a function (which is a line, in this case) cross(es) the "x-axis".
In other words, what is (are) the point(s) of the graph at which " y = 0 <span>" ?
</span>
By examining the graph, we see that when " y = 0 " ; x is equal to: "0.5<span>" .
</span>
So; the "x-intercept" is at point: "(0.5, 0)" ; or, we can simply say that the
"y-intercept" is: "0.5 " .<span>
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This would correspond to:<span>
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Answer choice: [D]: </span>" x-int: 1 , y-int: 0.5 " .
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{that is; The "x-intercept" is: "0" ; and the "y-intercept" is: "0.5 ".} .
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Answer:
p = 7
Step-by-step explanation:
set the expressions = to each other
4(n+7) = 4(n+p)
distribute the 4 on both sides(multiplying the numbers on the inside)
4n+28 = 4n+4p
subtract the 4n from the right and left
28 = 4p
divide by 4
p = 7
Substitute the given point (3, -2) in each condition
(i) y < -3; y ≤ (2/3)x - 4
-2 < -3 → False
Therefore, it is not a solution.
[Since the values of x and y must satisfy both the conditions, if one of them does not satisfy the condition then it is not necessary to check the other one.]
(ii) y > -3; y ≥ 2/3x - 4
-2 > -3 → True
y ≥ 2/3x - 4
-2 ≥ -2 → True
Therefore, it is a solution.
(iii) y < -3; y ≥ 2/3x - 4
-2 < -3 → False
Therefore, it is not a solution.
(iv) y > -2; y ≤ 2/3x - 4
-2 > -2 → False
Therefore, it is not a solution.
Thereofore, the system of linear inequalities having the point (3, -2) in its solution set is y > -3; y ≥ 2/3x - 4. Hope it helps you.
