Answer:
D) Three of the reaction steps in gluconeogenesis would have prohibitively large, positive free energies if they used glycolytic enzymes for their catalysis.
Explanation:
The glycolytic enzymes catalyze the conversion of glucose to pyruvate, while gluconeogenesis enzymes catalyze the formation of carbohydrates from pyruvate.
The answer will be A because mitosis usually separate the sister chromatids to sister chromosomes to form two diploid cells. In meiosis, the goal is to have four haploid cells. To form that, cells need to undergo cell division two times. In the case of meiosis I, sister chromatids stay joined together until it reaches meiosis II. Then, the sister chromatids will separate starting at anaphase II in meiosis II. For example, if you start with 92 chromosomes (46 chromatids) during meiosis I, at meiosis II you will have two cells with 46 chromosomes (23 chromatids). By the end of meiosis II, you should form 4 haploid cells that contains 23 chromosomes.
Answer:
Plants have two distinct stages in their lifecycle: the gametophyte stage and the sporophyte stage. After reaching maturity, the diploid sporophyte produces spores by meiosis, which in turn divide by mitosis to produce the haploid gametophyte. The new gametophyte produces gametes, and the cycle continues.
Explanation:
