Answer:
The value of f(g(3) = 1,008
Step-by-step explanation:
<u>Step:-1</u>
Given f(x) =
and g(x) = 3x+9
h(x) = 12+x
Given g(x) = 3x+9
put x =3
g(3) = 3(3)+9
<u> g(3) = 18</u>
<u>Step :-(2)</u>
f(g(3)) = f(18)
f(g(3) = 3(18)^2 +2(18) (since f(x) =)
= 1,008
<u>Final answer</u>:-
The value of f(g(3) = 1,008
Answer:
6 times whatever x is would be greater that -54
Answer:
4!
Step-by-step explanation:
In word MAXIMUM, consonants are M & X. According to the question itself, consonants should not occur together.
So, we have to put vowels at each even position; only then the condition will be satisfied.
We can put this in 3! ways (permutations of A, I & U).
For odd positions we can put 3-M's & a X. Total ways is 4!/3! (as repetitions of M).
Hence, the answer is 4!/3! x 3! = 24 ways.
24=4!.
Answer:
I believe the answer is C.
Step-by-step explanation:
Example:
For any angles A and B , if ∠ A ≅ ∠ B , then ∠ B ≅ ∠ A . Order of congruence does not matter.
Rewriting the equation as a quadratic equation equal to zero:
x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
(x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
x + 5 = 0 => x = -5
x - 6 = 0 => x = 6
Therefore, our solutions are x = -5 and x = 6.
