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3 years ago

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A student studying for a vocabulary test knows the meanings of 16 words from a list of 24 words. If the test contains 10 words f

rom the study list, what is the probability that at least 8 of the words on the test are words that the student knows?

1 answer:

nadya68 [22]3 years ago

3 0

There is a .383 chance of probability that he/she knows at least 8 of the words on the test.

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Sara drives 185 miles in 3 hours. If she

guajiro [1.7K]

I thinks its 740 miles

7 0

3 years ago

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0

3 years ago

Suppose that 2000 is invented at a rate of 3.5%, compounded semiannually. Assuming that no withdrawals are made, find the total

Vinvika [58]

Answer:

$2,297.76

Step-by-step explanation:

Present value: P = 2000

Future value: F

Annual interest rate: r = 3.5% = 0.035

Time: t = 4 years

Number of compounding periods per year: n = 2

$F = P(1 + \dfrac{r}{n})^{nt}$

$F = 2000(1 + \dfrac{0.035}{2})^{2 \times 4}$

$F = 2000(1 + 0.0175)^{8}$

$F = 2000(1.0175)^{8}$

$F = 2000(1.148881783)$

$F = 2297.76$

Answer: $2,297.76

6 0

3 years ago

Ava is thinking of a four-digit number described below.

ehidna [41]

<u>4</u><u>1</u><u>7</u><u>3</u>

Hope this helped you- have a good day bro cya)

3 0

3 years ago

Read 2 more answers

What is the volume of a box that will hold exactly 567 of these cubes with 1/3inch sides

Helen [10]

Answer:21

Step-by-step explanation:each cube has a volume of (1/3)^3 = 1/27 in^3

so, the total volume is 567/27 = 21 in^3

3 0

4 years ago