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3 years ago

Graph the solution of the inequality.

Mathematics

1 answer:

guapka [62]3 years ago

5 0

Answer:

$\displaystyle -16 < x$

Step-by-step explanation:

$\displaystyle -4[\frac{x}{-4}] < 4[-4] → x > -16$

Whenever you divide\multiply by a negative, you reverse the inequality symbol.

** The above answer is written in reverse, which is the exact same result.

≥, ≤ → Solid Circle [●]

>, < → Blank Circle [○]

I am joyous to assist you anytime.

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HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Genrish500 [490]

Answer:

Well, I don't know how to graph it for you, but the slope is -2/3 and the point is (-9, 5). So, when you graph it, from the point (-9, 5), you can go 3 units to the right and 2 units down.

6 0

3 years ago

According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e

slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that $p = 0.09$

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225$

$P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827$

$P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082$

$P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982$

Finally

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180$

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0

3 years ago

What is the area? Please explain steps so I can attempt to understand

yarga [219]

Answer:

$12 \sqrt{2}$

Step-by-step explanation:

you can use hypotenuse formula

45-45-90 isosceles right triangle

so, 45= x

x² + x² = 24²

2x² = 24²

x²= 24.12

x= $\sqrt{288} = 12 \sqrt{2}$

or :

you can use this rule: if you see a 45 45 90 isosceles right triagngle (you can look picture) 45=a cm and 90 = $a\sqrt{2}$

so ;

$a \sqrt{2} = 24$

a= $12 \sqrt{2}$

hope this helps ^-^

3 0

3 years ago

Checking account a has a service fee of $3 and a per check fee of $0.02 while checking account b charges a monthly fee of $2

Alecsey [184]

Idk how to answer this

6 0

3 years ago

Read 2 more answers

5 Points

deff fn [24]

Answer:

D. A rectangle and an isosceles triangle

Step-by-step explanation:

In the figure attached, the sign is shown. There we can see an arrow, which can be decomposed into a rectangle (on the left of the figure) and an isosceles triangle (on the right of the figure)

7 0

3 years ago