Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so
Answer: I belive the answer would be 18 the only number we have is 52 and 36 the other answers just don't make sense, I am only taking 9th grade but hey I try!
Step-by-step explanation:
<span>–4(x + 3) ≤ –2 – 2x
>>.....-4x -12 </span>≤ -2 -2x
>> -12 +2 ≤ +2x
>> - 10 ≤ 2x
>> -5 ≤ x............>> x >= -5
This answer is not represented in the pictures you attached
The line starts in x = -5 and goes up to infinity
Answer:
44
Step-by-step explanation:
Lunch = 3 appetizers per guest
If there are 22 guests: 22 × 3 = 66 appetizers served
Dinner = 5 appetizers per guest
If there are 22 guests: 22 × 5 = 110 appetizers served
Difference = total dinner appetizers - total lunch appetizers
= 110 - 66
= 44
Answer:
The Median of those numbers is 4
Step-by-step explanation:
