Answer:
Division is not associative.
The associative property applies only to addition and multiplication, not subtraction or division.
Let's call job one x.
Job two can be y.
Jason earned $3,700 more from job y than x. Therefore y = x + 3700
From the two jobs, Jason earned $15,900. This can be written as x + y = 15900.
Now substitute y for x + 3700:
x + x + 3700 = 15900
2x + 3700 = 15900
Subtract 3700 from both sides:
2x = 12200
Divide both sides by 2:
x = 6100
Take the original equation x + y = 15900 and substitute x with 6100:
6100 + y = 15900
y = 9800
Job one (x) paid Jason $6,100.
Job two (y) paid Jason $9,800.
Answer:
(look in the the Step by step)
Step-by-step explanation:
When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.
.. A = (1/2)*d₁*d₂
Substituting the given information, this becomes
.. 58 in² = (1/2)*(14.5 in)*d₂
.. 2*58/14.5 in = d₂ = 8 in
The length of diagonal BD is 8 in.
Answer:
(0,1) and (-2,9)
Step-by-step explanation:
A point (x,y) lies on the graph of f(x) = 
if it satisfies the condition y =
<h3>
(0,1):</h3>
x = 0 and y = 1.
This point satisfies the required condition as
= 1
Hence, this point <u>is</u> on the graph of f(x) =
<h3>
(3,27):</h3>
x = 3 and y = 27.
This point doesn't satisfy the required condition as
= 
≠ 27
Hence, this point i<u>s not</u> on the graph of f(x) =
<h3>
(-2,9):</h3>
x = -2 and y = 9.
This point satisfies the required condition as
= 
= 9
Hence, this point <u>is</u> on the graph of f(x) =
<h3>
(-1,
):</h3>
x = -1 and y = .
This point satisfies the required condition as
y = 
= 
= 3 ≠
Hence, this point <u>is not</u> on the graph of f(x) =
