Answer:
(x − 2) = 3
Remove the bracket
x - 2 = 3
Group the constants at one side of the equation
x = 2 + 3
x = 5
Therefore x = 5.00 to 3 significant figures.
Hope this helps
Answer: Ann = 67 Josh = 60 Claire = 30
Step-by-step explanation: You get the equation 5x+7 = 157. You get the equation because for example, Claire = x then josh = 2x and Ann = 2x + 7. You do all the math and boom! You get the answer :)
Answer: 1.9
Step-by-step explanation:
because you keep adding 1.9 to get your result
Answer:
Please check the explanation.
Step-by-step explanation:
<u>Calculating the area of the outer rectangle:</u>
Given
- The length outer rectangle = l = 3x - 1
- The width of outer rectangle = w = 5x + 2
Thus,
The area of the outer rectangle:





<u>Calculating the area of the inner rectangle:</u>
Given
- The length inner rectangle = l = x + 7
- The width of inner rectangle = w = x
Thus,
The area of the outer rectangle:
A = wl
= x(x+7)
= x² + 7
<u>Calculating the area of the shaded region:</u>
As
The area of the outer rectangle = 15x² + x - 2
The area of the inner rectangle = x² + 7
- The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.
Thus,
shaded region Area = Outer Rectangle Area - Inner Rectangle Area
= 15x² + x - 2 - (x² + 7)
= 15x² + x - 2 - x² - 7
= 14x² + x - 9
Therefore, the Area of the shaded region is: 14x² + x - 9
Answer:
The limit of the function does not exists.
Step-by-step explanation:
From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.
For x<2

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.
For x>2

The value of y is 1 at x=2, because of he close circles on (2,1).
For x=2

Therefore the graph represents a piecewise function, which is defined as

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.



Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.