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jekas [21]
3 years ago
12

You wish to prove that three propositions p1, p2, and p3 are equivalent. will it suffice to show that p1 --> p2, p2 --> p3

, and p3 --> p1? justify your answer
Mathematics
1 answer:
kompoz [17]3 years ago
5 0

Answer:

It is sufficient to prove that  p_1\implies p_2, p_2\implies p_3, p_3\implies p_1

Step-by-step explanation:

The propositions p_1,p_2,p_3 being equivalent means they should always have the same truth value. If one of them is true, then all of them must be true. And if one of them is false, then all of them must be false.

Suppose we've proven that p_1\implies p_2, p_2\implies p_3, p_3\implies p_1 (call these first, second and third implications).

If p_1 was true, then by the first implication that we proved, it would follow that p_2 is also true. And then by the second implication that we prove it would follow then that p_3 is also true. Therefore the three of them would be true. Notice the reasoning would have been the same if we had started assuming that the one that was true was either p_2~or~p_3. So one of them being true makes all of them be true.

On the other hand, if p_1 was false, then by the third implication that we proved, it would follow that p_3 has to be false (otherwise p_1 would have to be true, which would be a contradiction). And then, since p_3 is false, by the second implication that we proved it would follow that p_2 is false (otherwise p_3 would have to be true, which would be a contradiction). Therefore the three of them would be false. Notice the reasoning would have been the same if we had started assuming that the one that was false was either p_2~or~p_3. So one of them being false makes all of them be false.

So, the three propositions always have the same truth value, and so they're all equivalent.

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3 years ago
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(b) Neither is employed,

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max2010maxim [7]

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The point where a line or curve crosses the y-axis of a graph is y intercept

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