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nata0808 [166]
3 years ago
10

The product of a number and 4 increased by 16 is -2

Mathematics
1 answer:
NikAS [45]3 years ago
3 0

Let n = the unknown number

"The product of a number and 4" = 4 * n = 4n

"increased by 16" = + 16

Set it all equal to - 2.

4n + 16 = - 2

Subtract 16 from both sides to get constants on one side and variables on the other.

4n = - 2 - 16

Combine like terms:

4n = - 18

Divide both sides by 4 to isolate variable n.

n = - 18 / 4

= - 4 and 2/4 = - 4 and 1/2

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If the probability of p(m and n) =0.2 p(m)=0.4 and m and independent events, what is p(n)?
abruzzese [7]

Answer:

P(n) = 0.5

Step-by-step explanation:

For two events which are independent, we use the multiplication rule which states P (A and B) = P(A) * P(B). Substitute P(m) = 0.4 and P(m and n) = 0.2 into this formula.

P (m and n) = P(m) * P(n)

0.2 = 0.4*P(n)

Divide by 0.4 on both sides.

0.2 / 0.4 = P(n)

0.5 = P(n)

4 0
3 years ago
Can some one help me with this
tangare [24]

Answer:

t=(-13)

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

12t−8t=−52

12t+−8t=−52

(12t+−8t)=−52(Combine Like Terms)

4t=−52

4t=−52

Step 2: Divide both sides by 4.

4t /4 = −52 /4

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How do you write 41.344 in word form
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2 years ago
Select the correct answer. Given the equations `9x + (3)/(4)y = 6` and `2x + (1)/(2)y = 9`, by what factor would you multiply th
Minchanka [31]

-3/2 is the  factor would multiply the second equation to eliminate y.

The correct option is (C).

<h3>What is factor?</h3>

A number or algebraic expression that divides another number or expression evenly—i.e., with no remainder.

Given equation is :

9x+3/4 y =6

2x+1/2 y =9

If we have to eliminate the y variable so we have to multiply it by factor -3/2

Then the second equation become

-3/2(2x+1/2 y =9)

-3x- 3/4 y =- 27/2

As we can see the y variable of both the equation is same.

Hence, -3/2 is the  factor would multiply the second equation to eliminate y.

learn more about this concept here:

brainly.com/question/24182713

#SPJ1

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2 years ago
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