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Lelechka [254]
3 years ago
10

Find distance formula between (-9, 1) & (-5, -2)

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0
The "distance formula" is a result of the Pythagorean Theorem:

h^2=x^2+y^2, where h is the hypotenuse of a right triangle and x and y are the side lengths.

The distance formula then becomes:

d^2=((x2-x1)^2+(y2-y1)^2

In this case:

d^2=(-5--9)^2+(-2-1)^2

d^2=4^2+(-3)^2

d^2=16+9

d^2=25

d=√25

d=5 units
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Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.
katrin [286]

x=5.38 . Correct option C)5.38

<u>Step-by-step explanation:</u>

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.  picture is attached  . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x

By Pythagoras Theorem ,

Hypotenuse^2=Perpendicular^2+base^2

⇒ x^2=(3.6)^2+(4)^2

⇒ x=\sqrt{(3.6)^2+(4)^2}

⇒ x=\sqrt{12.96+16}

⇒ x=\sqrt{28.96}

⇒ x=5.38

Therefore , x=5.38 . Correct option C)5.38

6 0
3 years ago
How do you check the answer of -6 = x/3
viktelen [127]

Answer:

-6 = x / 3         -Multiply both sides by 3

-6 * 3 = x / 3 * 3

-18 = x

Now, you can check your answer:

-6 = -18 / 3

-6 = -6

Hope this helps!

8 0
3 years ago
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

4 0
3 years ago
1-25. Given f(x) =- 2/3x +3 and g(x) = 2x2 - 5, complete parts (a) through (f).
Korolek [52]

Answer:

When f or g are equivalent to a number you are solving for x. For example b, d, e, f. In the equation g(x) =2x2-5 I assumed 2 was a typo. So, if it's incorrect, please use same steps and just adjust the solution.

Step-by-step explanation:

f(x)=-\frac{2}{3x}+3

a) f(3)=-\frac{2}{2(3)} +3

           =-\frac{1}{3}+3 =\frac{-1+6}{3} =\frac{5}{3}

b) f(x)=-5

      -5=-\frac{2}{3x}+3

      -8=-\frac{2}{3x}

  -24x=-2

        x=\frac{1}{12}

g(x)=2x-5

c) g(-3)=2(-3)-5

               =-6-5

               =-11

d) g(x)=-7

      -7=2x-5

      -2=2x

        x=-1

e) g(x)=8

        8=2x-5

       12=2x

        x=6

f)  g(x)=9

         9=2x-5

        11=2x

         x=\frac{11}{2}

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7
zhenek [66]

Answer:

2

Step-by-step explanation:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}

\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}

\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}

3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}

(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0
3 years ago
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