Answer:
-84 + 10i
Step-by-step explanation:
first, you want to take out the negative symbol from the square root, and we know that i = sqrt(-1) (sqrt = square root)
so the equation would look like
i x sqrt(100) - 84
solve for the square root of 100 which is 10
now the equation is
10i - 84
that is the answer and you can flip the equations so it can look like the actual answer
-84 + 10i
Answer:
B:-1
Step-by-step explanation:
Just took test 2021
Answer:
A
Step-by-step explanation:
Refer to the picture.
Step 1: expand the bracket
Step 2: bring like terms together (e. G. Numbers, algebra like terms)
Step 3: simplify equation
Step 4: rearrange algebraic form to see which order fits the answer.
Answer:
One order pair is
(
2,0)
Step-by-step explanation:
What ordered pairs are the options?
Pick a value for
x
and solve for
y
. Or find the intercepts.
If
x
=
2
, then:
y
=
2
−
2
⇒
y
=
0
So we have
(
2
,
0
)
If
x
=
0
, then:
y
=
0
−
2
⇒
y
=
−
2
Here we have
(
0
,
−
2
)
You can simply use
0
for both
x
and
y
(intercept) to get the same answer.
Answer: Area of ΔABC is 2.25x the area of ΔDEF.
Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

with a as side of the triangle.
Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:
a₁ = 1.2a
Then, its area is


Triangle DEF is 20% smaller than the original, which means its side is:
a₂ = 0.8a
So, area is


Now, comparing areas:

2.25
<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>