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3 years ago

2(x+4)+6=22 solve for x

Mathematics

2 answers:

hjlf3 years ago

7 0

Answer:

X=4

Step-by-step explanation:

Subtract 6 from both sides

2(x+4)=22−6

Simplify 22-6 to 16

2(x+4)=16

Divide both sides by 2

x+4=16/2

Simplify 16/2 to 8

x+4=8

Subtract 4 from both sides

x=8-4

Simplify 8-4 to 4

X=4

hram777 [196]3 years ago

6 0

2x+8+6=22
2x+14-14=22-14
2x = 8
2x/2 = 8/2
x = 4
Check your work
2(4+4)+6=22
2(8)+6=22
16+6=22
22=22

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LekaFEV [45]

Answer:

B. In step 2, marquis should have interpreted the results as x _< - 9.2, which means that x is less than or equal to -9.2

Step-by-step explanation:

Step 1 is correct.

Step 2.

-9.2 >= x

Subtract x from both sides.

-x - 9.2 >= 0

Add 9.2 to both sides.

-x >= 9.2

Divide both sides by -1. When you multiply or divide both sides of an inequality, the inequality sign changes direction.

x <= -9.2

The first error is in Step 2.

Answer:

B. In step 2, marquis should have interpreted the results as x _< - 9.2, which means that x is less than or equal to -9.2

8 0

3 years ago

Read 2 more answers

zach is 23 years old. Zach's age is 3 years older than twice Maya's age. Let m represent Maya's age. What equation can be used t

PolarNik [594]

2m+3=23
2m=20
m=10
let me know in the comments if you need further explanation :)

5 0

3 years ago

I now have another question to ask.

marissa [1.9K]

Answer:

23.6 ft

Step-by-step explanation:

Sketch a right triangle representing this situation. The length of the hypotenuse is 26 ft and the angle of elevation from ground to top of ladder is 65°. The "opposite side" is the reach of the ladder, which we'll call x.

Then:

opp

sin 65° = ----------
26 ft

or (26 ft)(sin 65°) = opp side = height off the ground of top of ladder.

Evaluating this, we get:

(26 ft)(0.906) = 23.56 ft, or, rounded off, 23.6 ft

The ladder reaches 23.6 ft up the side of the building.

8 0

3 years ago

Let Z={a,c,{a,b}}. What is |Z|?

Lina20 [59]

$Z=\{a,c,\{a,b\}\}$

$\boxed{|Z|=3}$ (treat $\{a,b\}$ as one element of $Z$ )

The power set of $Z$ is

$\boxed{2^Z=\bigg\{\{\},\{a\},\{c\},\big\{\{a,b\}\big\},\{a,c\},\big\{a,\{a,b\}\big\},\big\{c,\{a,b\}\big\},\big\{a,c,\{a,b\}\big\}\bigg\}}$

1. $\{a,c\}\subseteq Z$ is true because both $a\in Z$ and $c\in Z$ .

2. $a\in Z$ is true.

3. $\{c\}\subseteq Z$ is true (same reason as part 1).

4. $\{c\}\in Z$ is false because $Z$ does not contain the set $\{c\}$ , rather just the element $c$ itself.

5. $b\in Z$ is false because the element $b$ on its own simply is not in $Z$ . That $b\in\{a,b\}$ does not mean $b\in Z$ , but that $b$ belongs to a subset of $Z$ .

6. $\{a,b\}\in Z$ is true.

6 0

3 years ago

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0

3 years ago