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Sauron [17]
3 years ago
10

5^4-x^2+x-2 divided by x - 2

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0

Answer: x −x  3  +x  2  +623x−2

​

Step-by-step explanation:

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Solve the equations
Minchanka [31]

Answer:

#1 - All real numbers are solutions.

#2 - All real numbers are solutions.

Step-by-step explanation:

#1 -

Let's solve your equation step-by-step.

12(6t−4)=3t−2

Step 1: Simplify both sides of the equation.

12(6t−4)=3t−2

(12)(6t)+(12)(−4)=3t+−2(Distribute)

3t+−2=3t+−2

3t−2=3t−2

Step 2: Subtract 3t from both sides.

3t−2−3t=3t−2−3t

−2=−2

Step 3: Add 2 to both sides.

−2+2=−2+2

0=0

Same for #2

8 0
3 years ago
suppose you invest 400 at an annual interest rate of 7.6% compounded continuously. How much will you have in the account after 1
dlinn [17]
A=pe^rt
A=400×e^(0.076×1.5)
A=448.30
3 0
3 years ago
Read 2 more answers
What is the least common denominator for 3/10 and 7/8?
Helen [10]
3/10 <7/8
Please my answer
6 0
3 years ago
Choose the function whose graph is given by:
wolverine [178]

<em>Greetings from Brasil...</em>

In a trigonometric function

F(X) = ±UD ± A.COS(Px + LR)

UD - move the graph to Up or Down (+ = up | - = down)

A - amplitude

P - period (period = 2π/P)

LR - move the graph to Left or Right (+ = left | - = right)

So:

A) F(X) = COS(X + 1)

standard cosine graph with 1 unit shift to the left

B) F(X) = COS(X) - 1 = -1 + COS(X)

standard cosine graph with 1 unit down

C) F(X) = COS(X - 1)

standard cosine graph with shift 1 unit to the right

D) F(X) = SEN(X - 1)

standard Sine graph with shift 1 unit to the right

Observing the graph we notice the sine function shifted 1 unit to the right, then

<h3>Option D</h3>

<em>(cosine star the curve in X and Y = zero. sine start the curve in Y = 1)</em>

7 0
2 years ago
Read 2 more answers
7. The largest of the Great Pyramids in Egypt was built with a square base,
strojnjashka [21]

Answer:

Difference between the original and current volumes = 4013140.30 cubic feet

Step-by-step explanation:

Largest pyramid has the square base with one edge = 754 feet

Area of the square base = (Side)²

                            = (754)²

                            = 568516 square feet

Volume of the pyramid = \frac{1}{3}(\text{Area of the base})(\text{Height})

                                       = \frac{1}{3}\times 568516\times 481

                                       = 91152065.3 cubic feet

After erosion,

Area of the base = (745)² = 555025 square feet

Volume of the pyramid = \frac{1}{3}(555025)(471)

                                       = 87138925 cubic feet

Difference between the original and current volumes of the pyramid

= 91152065.30 - 87138925

= 4013140.30 cubic feet

5 0
3 years ago
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