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inna [77]
3 years ago
13

What the equivalent expression. 5 (3m +2p) - 4m​

Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0
Hi the answer is 11m+10p
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12 picks in all . 1 out of 4 picks are orange . the rest are green . How many picks are orange ?
makvit [3.9K]
For every 4 picks there is 1 orange pick, so 12/4 should be fine
7 0
4 years ago
Need to find the direction angle for each vector. #10 and #12 please!
crimeas [40]

Answer:

10)  - 45 degrees

12)  0 degrees

Step-by-step explanation:

10)

Find the x and y components that define the vector that joins C with D:

x-component: -4 - (-8) = - 4 + 8 = 4

y-component:  4 - 8 = -4

use the tangent function to find the angle \theta:

tan(\theta)=\frac{y-comp}{x-comp}=\frac{-4}{4}  = -1\\\theta = -45^o

12)

Find the x and y components that define the vector that joins A with B:

x-component: 7 - 4 = 3

y-component:  - 1 - (-1) = -1 + 1 = 0

use the tangent function to find the angle \theta:

tan(\theta)=\frac{y-comp}{x-comp}=\frac{0}{3}  = 0\\\theta = 0^o

5 0
4 years ago
What is the sum of 1/6 and 5/12​
torisob [31]

Answer:

7/12

1/6 to 2/12 add 5/12 to get 7/12

3 0
2 years ago
The first CORRECT answer will receive Brainliest. If you can’t see zoom in. If you have any questions click the three dots next
myrzilka [38]

Answer:

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5 0
3 years ago
Y=x^2-6x-16 in vertex form
satela [25.4K]

Answer:

y=(x-3)^{2} -25

Step-by-step explanation:

The standard form of a quadratic equation is y=ax^{2} +bx+c

The vertex form of a quadratic equation is y=a(x-h)^{2} +k

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

h=\frac{-b}{2a}

In this case, our quadratic equation is y=x^{2} -6x-16. Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

h=\frac{-b}{2a} ⇒ h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is y=x^{2} -6x-16

y=x^{2} -6x-16 ⇒ y=(3)^{2} -6(3)-16 ⇒ y=9-18-16 ⇒ y=-25

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: y=a(x-h)^{2} +k

a: 1

h: 3

k: -25

y=(x-3)^{2} -25

Hope this helps!

3 0
3 years ago
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