The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
Answer:
However much he had on his card in the first place.
Step-by-step explanation:
Say he had $500 on his card. He took 0 rides ( no rides ) so he doesn't lose any money. Leaving him with his starting amount, $500.
Answer:
the person above is right it's 4.5 units
give them the crown
Answer:
Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).
Step-by-step explanation:
Misha's group was asked to write an expression equivalent to
7y²z + 3yz² - 3
When Mr. Chen checked their answers, he found only one to be correct.
And she was Helena.
Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).
Because, (7y²z + 6yz²- 5 - 3yz² + 2)
= 7y²z + (6yz² - 3yz²) - (5 - 2)
= 7y²z + 3yz² - 3 (Answer)
