The present value (PV) of a loan for n years at r% compounded t times a year where there is equal P periodic payments is given by:
Given that <span>Beth
is taking out a loan of PV = $50,000 to purchase a new home for n = 25 years at an interest rate of r = 14.25%. Since she is making the payment monthly, t = 12.
Her monthly payment is given by:
Therefore, her monthly payment is about $611.50
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Given;
6Ln (x + 2.8) = 9.6
We will transpose 6 in the Ln, so that we will leave Ln alone.
Ln (x + 2.8) = 9.6/6 = 1.6
we divide the 9.6 to 6 and we get 1.6
x + 2.8 = e^1.6
e^ for the substitution of Ln
x = e^1.6 - 2.8
insert the e^(1.6) in the calculator and you will get 4.95303242439511 and subtract 2.8 and you will get the answer.
x = 2.153
2.153 is the final answer in this question.
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
Answer:
answer is:
Step-by-step explanation:
we are asked to find which system of equations can we use to find the roots of the equation:
since the system of equation in last part is given as:
so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:
.
The inverse of the equation is the square root of x-16. In order to find inverse switch the y and x values and try to isolate y
