Jayden wants to take a current theme but just change a little bit of it. Complete the steps to help Jayden.
1 answer:
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Answer:
I am writing the program in JAVA and C++
JAVA:
public int createLicenseNum(int customID){ //class that takes the customID as parameter and creates and returns the licenseNum
licenseNum = (100000 * customID) + licenseYear; //licenseNum creation formula
return(licenseNum); }
In C++ :
void DogLicense::CreateLicenseNum(int customID){ //class that takes the customID as parameter and creates the licenseNum
licenseNum = (100000 * customID) + licenseYear; } //licenseNum creation formula
Explanation:
createLicenseNum method takes customID as its parameter. The formula inside the function is:
licenseNum = (100000 * customID) + licenseYear;
This multiplies 100000 to the customID and adds the result to the licenseYear and assigns the result of this whole expression to licenseNum.
For example if the SetYear(2014) means the value of licenseYear is set to 2014 and CreateLicenseNum(777) this statement calls createLicenseNum method by passing 777 value as customID to this function. So this means licenseYear = 2014 and customID = 777
When the CreateLicenseNum function is invoked it computes and returns the value of licenseNum as:
licenseNum = (100000 * customID) + licenseYear;
= (100000 * 777) + 2014
= 77700000 + 2014
licenseNum = 77702014
So the output is:
Dog license: 77702014
To call this function in JAVA:
public class CallDogLicense {
public static void main(String[] args) {//start of main() function
DogLicense dog1 = new DogLicense();//create instance of Dog class
dog1.setYear(2014); // calls setYear passing 2014
dog1.createLicenseNum(777);// calls createLicenseNum passing 777 as customID value
System.out.println("Dog license: " + dog1.getLicenseNum()); //calls getLicenseNum to get the computed licenceNum value
return; } }
Both the programs along with the output are attached as a screenshot.
Answer:
<h2>Function 1:</h2>#include <stdio.h> //for using input output functions
// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter
void PrintPopcornTime(int bagOunces){
if (bagOunces < 3){ //if value of bagOunces is less than 3
printf("Too small"); //displays Too small message in output
printf("\n"); } //prints a new line
//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10
else if (bagOunces > 10){
printf("Too large"); //displays the message: Too large in output
printf("\n"); //prints a new line }
/*the following else part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */
else {
/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */
//int result;
//result = bagOunces * 6;
//printf("%d",result);
printf("%d",bagOunces * 6); /multiplies value of bagOunces to 6
printf(" seconds");
// seconds is followed with the value of bagOunces * 6
printf("\n"); }} //prints a new line
int main(){ //start of main() function body
int userOunces; //declares integer variable userOunces
scanf("%d", &userOunces); //reads input value of userOunces
PrintPopcornTime(userOunces);
//calls PrintPopcornTime function passing the value in userOunces
return 0; }
Explanation:
<h2>Function 2: </h2>#include <stdio.h> //header file to use input output functions
// start of the function PrintShampooInstructions body having integer variable numCycles as parameter
void PrintShampooInstructions(int numCycles){
if(numCycles < 1){
//if conditions checks value of numCycles is less than 1 or not
printf("Too few."); //prints Too few in output if the above condition is true
printf("\n"); } //prints a new line
//else if part is executed when the if condition is false and else if checks //value of numCycles is greater than 4 or not
else if(numCycles > 4){
//prints Too many in output if the above condition is true
printf("Too many.");
printf("\n"); } //prints a new line
//else part is executed when the if and else if conditions are false
else{
//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done
for(int N = 1; N <= numCycles; N++){
printf("%d",N);
printf(": Lather and rinse. \n");}
printf("Done.");
printf("\n");} }
int main() //start of the main() function body
{ int userCycles; //declares integer variable userCycles
scanf("%d", &userCycles); //reads the input value into userCycles
PrintShampooInstructions(userCycles);
//calls PrintShampooInstructions function passing the value in userCycles
return 0;}
I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by
printf(": Lather and rinse. \n"); which is followed by printf("Done.");
So at first iteration:
printf("%d",N); prints 1 as the value of N is 1
printf(": Lather and rinse. \n"); prints : Lather and rinse and prints a new line \n.
As a whole this line is printed on the screen:
1: Lather and rinse.
Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.
Now at second iteration:
The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles which means 2=2. So the program control enters the body of loop.
printf("Done."); prints Done after the above two lines.
printf("%d",N); prints 2 as the value of N is 2
printf(": Lather and rinse. \n"); prints : Lather and rinse and prints a new line \n.
As a whole this line is printed on the screen:
2: Lather and rinse.
Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.
The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles which means 3>2. So the loop breaks.
Now the next statement is:
printf("Done."); which prints Done on the screen.
So as a whole the following output is displayed on the screen:
1: Lather and rinse.
2: Lather and rinse.
Done.
The programs along with their outputs are attached.
