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almond37 [142]
3 years ago
14

Please help me someone

Mathematics
1 answer:
kap26 [50]3 years ago
5 0

<u>Answer:</u>

The correct answer option is D. He multiplied the divisor by 100 and dividend by 10.

<u>Step-by-step explanation:</u>

We are given that Miguel completed the division where initially he had to divide 754 by 0.52.

To make it easier, he multiplied both the divisor and the dividend by the same number to get rid of the decimal in the divisor.

If he multiplied the divisor by 100, he should have multiplied the dividend by 100 too. But instead, he mistakenly multiplied the divisor by 100 and dividend by 10.

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Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

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valkas [14]

Answer: \boxed{y=\frac{4}{5}x-2}

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals, so as the slope of the given line is -5/4, the slope of the perpendicular line is 4/5.

Substituting into point-slope form,

y-6=\frac{4}{5}(x-10)\\\\y-6=\frac{4}{5}x-8\\\\\boxed{y=\frac{4}{5}x-2}

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2 years ago
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