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scoray [572]
3 years ago
7

What is the area of the polygon shown above? Show all your work. Please include the appropriate units in your answer.

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:24 by 5

Step-by-step explanation:

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11y^2-19y-10=-4y^2 <br> all real solutions
tangare [24]

Answer:

y=5/3 is the only real solution

Step-by-step explanation:

Solve for y over the real numbers:

11 y^2 - 19 y - 10 = -4 y^2

Add 4 y^2 to both sides:

15 y^2 - 19 y - 10 = 0

The left hand side factors into a product with two terms:

(3 y - 5) (5 y + 2) = 0

Split into two equations:

3 y - 5 = 0 or 5 y + 2 = 0

Add 5 to both sides:

3 y = 5 or 5 y + 2 = 0

Divide both sides by 3:

y = 5/3 or 5 y + 2 = 0

Subtract 2 from both sides:

y = 5/3 or 5 y = -2

Divide both sides by 5:

Answer: |

| y = 5/3 or y = -2/5

4 0
3 years ago
What is the value of x2 + 2y ÷ 2w + 3z for w = 2, x = 5, y = 8, and z = 3?
pav-90 [236]
The answer to this question is 23
5 0
3 years ago
Plz frist to answer will be brainliest​
Gelneren [198K]

Answer:

D

Step-by-step explanation:

p^2

3 0
3 years ago
Use the​ power-reducing formulas to rewrite the expression as an equivalent expression that does not contain powers of trigonome
ratelena [41]

Answer:

x = 0.175\cdot (1-\cos 4\cdot \theta)

Step-by-step explanation:

Let use the following trigonometric identities:

\sin^{2}\theta = \frac{1-\cos 2\cdot \theta}{2} \\\cos^{2}\theta = \frac{1+\cos 2\cdot \theta}{2}

Then, the equation is simplified by substituting its components:

x = 1.40\cdot \left(\frac{1-\cos 2\cdot \theta}{2}  \right)\cdot \left(\frac{1+\cos 2\cdot \theta}{2} \right)

x = 0.35\cdot (1-\cos^{2}2\cdot \theta)

x = 0.35\cdot \sin^{2}2\cdot \theta

x = 0.35\cdot \left(\frac{1-\cos 4\cdot \theta}{2}  \right)

x = 0.175\cdot (1-\cos 4\cdot \theta)

7 0
3 years ago
Read 2 more answers
Two points A and B are A (0,1) and B (2,4). Write down the eqaution of the line perpendicular to AB and Passing through the poin
Zielflug [23.3K]

Answer:

y = -2x/3 + 2

Step-by-step explanation:

A(0,1), B(2,4)

slope of AB = (yb-ya)/(xb-xa) = (4-1)/(2-0) = 3/2

Slope of perpendicular to AB

m = -1/(3/2) = -2/3

Point to lie on perpendicular, P(0,2)

Equation of perpendicular, point-slope form

(y-yp) = m(x-xp)

y-2 = -(2/3)(x-0)

y = -2x/3 + 2

6 0
3 years ago
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