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A diagram of parallelogram MNOP is attached below
We have side MN || side OP and side MP || NO
Using the rule of angles in parallel lines, ∠M and ∠P are supplementary as well as ∠M and ∠N.
Since ∠M+∠P = 180° and ∠M+∠N=180°, we can conclude that ∠P and ∠N are of equal size.
∠N and ∠O are supplementary by the rules of angles in parallel lines
∠O and ∠P are supplementary by the rules of angles in parallel lines
∠N+∠O=180° and ∠O+∠P=180°
∠N and ∠P are of equal size
we deduce further that ∠M and ∠O are of equal size
Hence, the correct statement to complete the proof is
<span>∠M ≅ ∠O; ∠N ≅ ∠P
</span>
We have side MN || side OP and side MP || NO
Using the rule of angles in parallel lines, ∠M and ∠P are supplementary as well as ∠M and ∠N.
Since ∠M+∠P = 180° and ∠M+∠N=180°, we can conclude that ∠P and ∠N are of equal size.
∠N and ∠O are supplementary by the rules of angles in parallel lines
∠O and ∠P are supplementary by the rules of angles in parallel lines
∠N+∠O=180° and ∠O+∠P=180°
∠N and ∠P are of equal size
we deduce further that ∠M and ∠O are of equal size
Hence, the correct statement to complete the proof is
<span>∠M ≅ ∠O; ∠N ≅ ∠P
</span>
Answer:
We want to graph the inequality:
3x - 2y ≤ 6
The first step is to write this as a linear equation, to do it, we can isolate y in one side of the inequality.
3x ≤ 6 + 2y
3x - 6 ≤ 2y
(3/2)x - 6/2 ≤ y
(3/2)x - 3 ≤ y
or:
y ≥ (3/2)x - 3
Because we have the symbol ≥
The points on the line are solutions, then the first part is to graph the line:
y = (3/2)*x - 3
Next, we have:
y equal to or larger than (3/2)*x - 3
Then we need to shade all the region above that line.
The graph can be seen below.
