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3 years ago

What is the answer

Mathematics

1 answer:

Reika [66]3 years ago

3 0

Answer:

35 mi²

Step-by-step explanation:

Let's subdivide the figure, as shown.

The lower part is a rectangle whose area is (5 mi)(18 mi) = 90 mi².

The upper part is a trapezoid whose area is found by averaging the length and multiplying the result by the width (8 mi - 5 mi), or 3 mi.

Area of trapezoid:

12 mi + 18 mi

------------------------ = 15 mi Width of trapezoid = 3 mi

Thus, the area of the trapezoid is (3 mi)(15 mi) = 45 mi²

and the total area of the entire figure is

45 mi² + 90 mi² = 135 mi²

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9. The expression x(x-7)+4(x-7) is equivalent to each of the following except which choice?

Rus_ich [418]

Answer:

I the answer is number 3

x(x-7)+4(x-7)

x²-7x + 4x-28

=x²-3x-28

(x+4)(x-7)

x²-7x+4x-28

=x²-3x-28

(x-7)(x+4)

x²+4x-7x-28

=x²-3x-28

x2 – 3x – 28

the factored form is

=(x+4)(x-7)

6 0

3 years ago

Water flows straight down from an open faucet. The cross-sectional area of the faucet is 1.00 × 10 − 4 m², and the speed of the

Setler79 [48]

Answer: $A_2=0.349\times 10^{-4} m^2$

Step-by-step explanation:

Given

velocity $v_1=0.72 m/s$

Area of cross-section $A_1=1\times 10^{-4} m^2$

velocity after Falling 0.19 m

$v_2^2-v_1^2=2g\cdot h$

$v_2^2=v_1^2+2g\cdot h$

$v_2^2=(0.72)^2+2\times 9.8\times 0.19$

$v_2^2=0.518+3.724$

$v_2=\sqrt{4.24}$

$v_2=2.05 m/s$

conserving Flow

$A_1v_1=A_2v_2$

$1\times 10^{-4}\times 0.72=A_2\times 2.05$

$A_2=0.349\times 10^{-4} m^2$

8 0

3 years ago

Can someone help me with this please?!

posledela

Answer:

x < 6

Step-by-step explanation:

1) -5x > -30

2) divide both sides by -5

3) flip the sign as we divided inequality by a negative

4) x < 6

7 0

2 years ago

Find out for what value of the variable:

Burka [1]

Answer:

$a=-1,\ a=-5$

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Step-by-step explanation:

<u>Equations</u>

We have two cases where some variable is required to be found such that some condition is met. The first case is about finding the value of a that complies:

$a^2+7a+6=a+1$

Rearranging

$a^2+6a+5=0$

Factoring:

$(a+1)(a+5)=0$

There are two solutions:

$a=-1,\ a=-5$

The second case requires us to find the value of x such that

$3x^2-x+1 =2x^2+5x-4$

Rearranging

$x^2+4x+5=0$

This second-degree equation has no real roots. We'll offer the imaginary (complex) solutions:

$x=-2+i,\ -2-i$

5 0

3 years ago

Makir is saving up his money to buy a iPad that costs $475.99. Right now he has $196.00, and can save $45.00 each week. How many

ehidna [41]

Answer:
5 weeks
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5 0

3 years ago

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