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erma4kov [3.2K]
1 year ago
8

Simplify. final answer should be written in standard form (a+b)(3a-b)(2a+7b)

Mathematics
1 answer:
algol131 year ago
6 0

we have

(a+b)(3a-b)(2a+7b)

step 1

Solve

apply distributive property

(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2

step 2

Multiply (3a^2-4ab-b^2) by (2a+7b)

6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3

answer is

<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
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An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

6 0
3 years ago
In the figure below, ⎯⎯⎯⎯⎯⎯⎯⎯,⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯, and ⎯⎯⎯⎯⎯⎯⎯⎯⎯ are medians of △. If KC = 108 and OC = 2n+10, then n=
Nimfa-mama [501]

The question was incomplete. Below you will find the missing content.

In the figure below, BL, AM, and CK are medians of △ABC. If KC = 108 and OC = 2n + 10, then n=

The picture is attached below.

The value of n is 31.

The median is the line connecting the vertex and its midpoint on the opposite side of the triangle.

The intersection of all 3 medians of the triangle is called the centroid.

As we know centroid divides the median in the ratio of 2:1.

In the given picture,

Medians of triangle △ABC are AM, BL, and CK.

So the centroid of the triangle is O.

Given that KC= 108

As the centroid O divides the line KC in 2:1.

Let OC=2x

KO= X

As KC= KO+OC

⇒ 108= x+2x

⇒ 3x=108

⇒ x=108/3

⇒ x=36

Then OC= 2x= 2*36= 72

As given in the question OC= 2n+10

putting the value of OC in above equation

⇒ 72= 2n+10

⇒ 2n= 72-10

⇒ 2n=62

⇒ n=62/2

⇒n=31

Therefore the value of n is 31.

Learn more about the median of the triangle

here: brainly.com/question/2264495

#SPJ10

5 0
2 years ago
Which is the constant term of the algebraic expression -2x2 + 17 -15x + 7xy?
Over [174]
17 is the constant term because it does not have any variables.
5 0
3 years ago
The product of two integers is -12 and the sum is -1. What are the numbers?
kupik [55]

Answer:

+3 and -4

Step-by-step explanation:

as

+3×-4=-12

and

-4+3=-1

3 0
3 years ago
1. 1*1/6=___
Ratling [72]

Step-by-step explanation:

1. 1*1/6= 1 /6=1.67

2. 9*7/10= 63/10= 6.3

3. 7*4/8= 28/8= 3.5

4. 1/2 of 2= 1/2*2= 0.5*2= 1

5. 1/12 of 2= 1/12*2= 8.33*2= 16.66

6.2/6 of 2= 2/6*2= 3.33*2= 6.66

7. 1/3 of 5= 1/3*5= 3.33*5= 16.65

8. 3/10 of 8= 3/10*8= 0.3*8= 2.4

Hope it's help you ♥️

7 0
3 years ago
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