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erma4kov [3.2K]
1 year ago
8

Simplify. final answer should be written in standard form (a+b)(3a-b)(2a+7b)

Mathematics
1 answer:
algol131 year ago
6 0

we have

(a+b)(3a-b)(2a+7b)

step 1

Solve

apply distributive property

(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2

step 2

Multiply (3a^2-4ab-b^2) by (2a+7b)

6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3

answer is

<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
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<h3>To which sets does the number below belong?</h3>

Here we have the number 1/3.

First, remember that we define rational numbers as these numbers that can be written as a quotient between two integers.

Here 1 is an integer and 3 is an integer, then 1/3 is a rational number.

Also, the combination between the rational set and the irrational set is the set of the real numbers, then 1/3 is also a real number.

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