You would plot them by month, 170-110= 60 dollar increase. 60 divided by 12 ( for each month) leaves a 5 dollar increase each month. Your coordinates would be 0,110 1,115 2,120 3,125
x would be month
y would be money
All you have to do is multiply your number and then add them together !!
Answer: The first option.
Step-by-step explanation:
If you square you get 
x=0
Answer:
<em>84%</em><em> of the wage earners earn less than $14,000 each. </em>
Step-by-step explanation:
The Empirical Rule (68-95-99.7%)-
According to this around 95% of the data will fall within two standard deviations of the mean.
As the bell curve is symmetrical, so the remaining 5% will be divided into 2 equal parts. So 2.5% will be above 2 standard deviation and 2.5% will be below 2 standard deviation.
As it is given that, the top 2.5% of the wage earners earn $18,000 or more, so 18,000 is 2 standard deviation away from the mean 10,000.
i.e 
We know that,
where,
X = raw score = 14,000
μ = 10,000
σ = 4,000
Putting the values,
Now, calculating the value from the z score table,
As the probability at 
is the area below that, so 84% of the wage earners earn less than $14,000 each.
Given the table below which lists the masses and volumes of several pieces of the same type of metal.<span>
From the table the ratio of the mass to the volume of the metal of mass 34.932 is 34.932 / 4.1 = 8.52
</span><span>the ratio of the mass to the volume of the metal of mass 47.712 is 47.712 / 5.6 = 8.52
</span><span>the ratio of the mass to the volume of the metal of mass 61.344 is 61.344 / 7.2 = 8.52
</span><span><span>the ratio of the mass to the volume of the metal of mass 99.684 is 99.684 / 11.7 = 8.52
</span>MASS (grams) VOLUME (cubic cm.)
34.932 4.1
47.712 5.6
61.344 7.2
99.684 11.7</span>
Since the ratio of the various masses to the volume of the metals is the same, so there is a relationship between the mass and the volume of the piece of metal.
If the volume of a piece of metal is 15.3 cubic cm, then the mass of the metal is given by 15.3 * 8.52 = 130.356 grams.
