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Vadim26 [7]
3 years ago
14

Which of the following is the rule for the geometric sequence 1, 3, 9, 27, ...?

Mathematics
2 answers:
RoseWind [281]3 years ago
7 0

Answer:

D. an =1 x 3 n-1 is the correct answer.

Step-by-step explanation:

Dmitriy789 [7]3 years ago
4 0

Answer:

Multiply by three for every number 1*3 =3 3*3=9 9*3=27

Step-by-step explanation:

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for a field trip 4 students rode in cars and the rest filled nine buses. how many students were in each bus if 472 students were
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The answer is 52

x - the number of students in a bus

4 + 9x = 472
9x = 472 - 4
9x = 468
x = 468 / 9
x = 52
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Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
If f(x) = 5-2x^3 and f^-1 denotes the inverse function of f, then f^-1(x)= ?
-BARSIC- [3]
f(x)=5-2x^3\\
y=5-2x^3\\
2x^3=-y+5\\
x^3=-\dfrac{y-5}{2}\\
x=\sqrt[3]{-\dfrac{y-5}{2}}=-\sqrt[3]{\dfrac{y-5}{2}}\\
f^{-1}(x)=-\sqrt[3]{\dfrac{x-5}{2}}
7 0
3 years ago
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