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3 years ago

CAN SOMEONE HELP ME WITH REFLECTIONS??

Mathematics

1 answer:

wel3 years ago

3 0

Answer:

(5, 2 )

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

P(5, - 2 ) → P'(5, - (- 2)) → P'(5, 2 )

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-(-(8)))Explain how to answer

GuDViN [60]

$-(-(8))$

1. Remove the parenthesis using the next rules:

$\begin{gathered} -(+)=- \\ -(-)=+ \end{gathered}$

2. Start to remove the parentheses from the center to the edges:

$-(-(8))=-(-8)=+8=8$ <h2>Then, the solution is 8</h2>

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2 years ago

Approximate the stationary matrix S for the transition matrix P by computing powers of the transition matrix P.

Scrat [10]

Answer:

S = [0.2069,0.7931]

Step-by-step explanation:

Transition Matrix:

$P=\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

Stationary matrix S for the transition matrix P is obtained by computing powers of the transition matrix P ( k powers ) until all the two rows of transition matrix p are equal or identical.

Transition matrix P raised to the power 2 (at k = 2)

$P^{2} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

$P^{2} =\left[\begin{array}{ccc}0.2203&0.7797\\0.2034&0.7966\end{array}\right]$

Transition matrix P raised to the power 3 (at k = 3)

$P^{3} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

$P^{3} =\left[\begin{array}{ccc}0.2203&0.7797\\0.2034&0.7966\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

$P^{3} =\left[\begin{array}{ccc}0.2086&0.7914\\0.2064&0.7936\end{array}\right]$

Transition matrix P raised to the power 4 (at k = 4)

$P^{4} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

$P^{4} =\left[\begin{array}{ccc}0.2086&0.7914\\0.2064&0.7936\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

$P^{4} =\left[\begin{array}{ccc}0.2071&0.7929\\0.2068&0.7932\end{array}\right]$

Transition matrix P raised to the power 5 (at k = 5)

$P^{5} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

$P^{5} =\left[\begin{array}{ccc}0.2071&0.7929\\0.2068&0.7932\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]$

$P^{5} =\left[\begin{array}{ccc}0.2069&0.7931\\0.2069&0.7931\end{array}\right]$

P⁵ at k = 5 both the rows identical. Hence the stationary matrix S is:

S = [ 0.2069 , 0.7931 ]

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3 years ago

3 Which expression represents "6 more than x<br>a. x+6<br>b.x-6<br>c. 6x<br>d. 6-x

Colt1911 [192]

Answer:

a. x + 6

Step-by-step explanation:

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3 years ago

Water boils at sea level at 100°C. The boiling point of water decreases about 5°C for every mile above sea level. Santa Fe, New

KIM [24]

First lets convert feet to miles: if 1 mi = 5280 feet then 7200 feet / 5280 feet = 1.364 miles. Now we need to see how much degrees does the boiling point for water decreases: if 1 mile = 5 degrees Celsius, then 0.364 miles correspond to 0.364*5=1.82 degrees Celsius. So now we add the two values: 5+1.82 = 6.82 degrees Celsius. Now we find the decrease in the boiling point of water: 100-6.82 = 93.18 degrees Celsius. So at 7200 feet above sea level, in Santa Fe, the water boils at 93.18 degrees Celsius.

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3 years ago

3. STEM Air filters are rated based on the particle size that the

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Sport could get the answer

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3 years ago

CAN SOMEONE HELP ME WITH REFLECTIONS??​

CAN SOMEONE HELP ME WITH REFLECTIONS??