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Cerrena [4.2K]
3 years ago
10

(Q#7)I know the area of a rhombus is base times height( because it is a parallelogram), but I don't know which one is the height

and which is the base.

Mathematics
1 answer:
k0ka [10]3 years ago
6 0
The height is 14 and the base is 25
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A car is traveling at a steady speed. It travels 1 3/4 miles in 2 1/3 minutes. how far will it travel in 21 minutes? in 1 hour?
GaryK [48]

Answer:

Step-by-step explanation:

1¾ miles/(2⅓ minutes) = (7/4 miles)/(7/3 minutes) = ¾ mile/minute

21 minutes × ¾ mile/minute = 15.75 miles

60 minutes × ¾ mile/minute = 45 miles

8 0
2 years ago
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
2 years ago
What is the reciprocal of 5 1/8
Mars2501 [29]

Answer:

0.19512195122

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Solve this simultaneous equation x+2y=11 <br> x-2y=1
lana [24]

Answer:

Equation 1,

x + 2y = 11

Equation 2,

x - 2y = 11

Take equation number 2.

x  -  2y = 11 \\ x = 11  +  2y

Substitute 'x' in Equation number 1.

x + 2y = 11 \\ 11 + 2y + 2y = 11 \\ 11 + 4y = 11 \\ 4y = 11 - 11 \\ 4y = 0 \\ y =  \frac{0}{4}  \\ y = 0

<u>y = 0.</u>

So x,

x = 11 - 2y \\ x = 11 - 2(0) \\ x = 11 - 0 \\ x = 11

<u>x = 11.</u>

7 0
3 years ago
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What is the slope between the points (5,-4) and (-3,4) <br> -1<br> 4<br> 0<br> 1
kumpel [21]

Answer:

The answer is -1.

Step-by-step explanation:

You have to apply gradient formula :

m =  \frac{y2 - y1}{x2 - x1}

So you will have to substitute the coordinates into the equation. Let (x1,y1) be (-3,4) and (x2,y2) be (5,-4) :

m =  \frac{ - 4 - 4}{5 - ( - 3)}

m =  \frac{ - 8}{8}

m =  - 1

6 0
2 years ago
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