A sample histogram is attached.
Using intervals of width 5, we have
0-4, with a frequency of 6
5-9, with a frequency of 4
10-14, with a frequency of 3
15-19, with a frequency of 2
Answer:
$4.25
Step-by-step explanation:
Easy price is 85 so
Divide 85 by 100
0.85
then multiply by 5
0.85*5=4.25
Brainliest please and you're welcome
9 is 1/10 of 90 because if you add 1 zero it is 90
Answer:
56.52mm²
Step-by-step explanation:
Based on observation, sum of diameters of small circles = diameter of the big circle.
In question, diameter of big circle = 12 mm.
And radius of big circle = 12mm/2 = 6mm
Let the diameter of each small circle be '2a'. So, radius of each small = 2a/2 = a.
=> 2a + 2a = 12mm
=> 4a = 12mm
=> a = 3mm
=> radius of each small circle = 3mm
Area of big circle = πr²
= (3.14)(6mm)²
= 113.04 mm²
Area covered by 2 small circles is: 2 * area of 1 one circle.
=> 2 * π(3mm)² = 18π mm²
=> 56.52 mm²
Shaded area = total area - area of 2 circles = 113.04 - 56.52 mm² = 56.52 mm²
Answer:
23 miles.
Step-by-step explanation:
Using the given, 4 and 5.75, we can create an equation.
To create a valid equation, we must multiply 4 and 5.75 to find the total distance.
4(5.75) = T
T = the total distance of the bike ride.
<u>Solve</u><u>:</u>
4(5.75) = 23.
Your solution is 23 miles, the total distance of the bike ride.