we know that
An isosceles triangle is a triangle with two congruent sides. These congruent sides are called legs. The point at which these legs meet is called the vertex point of the isosceles triangle, and the angle formed by the legs is called the vertex angle. The other two angles of the triangle are called base angles.
see the attached figure to better understand the question
therefore
the answer is
Vertex angle
Area of the parallelogram = 20 x 16 = 320
Area of the triangle on top = 1/2 x 20 x 8 = 80
Total = 320 + 80 = 400 square inches
Answer:
28 squares
Step-by-step explanation:
column is 7 squares long, row is 4 squares long, 4x7 = 28 squares
<span>Given
equation = 1/6x – 5 = 1/5x + 2
how can it be set up as linear of equation?
let’s start solving the given equation to show the system of equations:
=> 1/6 x – 5 = y
=> 6y = x – 30
=> 6y – x = -30
=> 1/5 x + 2 = y
=> 5y = x + 10
=> 5y – x = 10
Thus, the system of equation of the given equations are:
=> 6y – x = -30</span><span>
=> 5y – x = 10</span>
Answer:
Step-by-step explanation:
We know:
We have
Use 
![\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B1%7D%7B2%7D%5Cright%29%5E2%2B%5Ccos%5E2%5Ctheta%3D1%5C%5C%5C%5C%5Cdfrac%7B1%7D%7B4%7D%2B%5Ccos%5E2%5Ctheta%3D1%5Cqquad%5Ctext%7Bsubtract%7D%5C%20%5Cdfrac%7B1%7D%7B4%7D%5C%20%5Ctext%7Bfrom%20both%20sides%7D%5C%5C%5C%5C%5Ccos%5E2%5Ctheta%3D%5Cdfrac%7B4%7D%7B4%7D-%5Cdfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%5Ccos%5E2%5Ctheta%3D%5Cdfrac%7B3%7D%7B4%7D%5Cto%5Ccos%5Ctheta%3D%5Cpm%5Csqrt%7B%5Cdfrac%7B3%7D%7B4%7D%7D%5Cto%5Ccos%5Ctheta%3D%5Cpm%5Cdfrac%7B%5Csqrt3%7D%7B%5Csqrt4%7D%5Cto%5Ccos%5Ctheta%3D%5Cpm%5Cdfrac%7B%5Csqrt3%7D%7B2%7D%5C%5C%5C%5C%5Ctheta%5Cin%5B0%5Eo%2C%5C%2090%5Eo%5D%2C%5C%20%5Ctext%7Btherefore%20all%20functions%20have%20positive%20values%20or%20equal%200.%7D%5C%5C%5C%5C%5Ccos%5Ctheta%3D%5Cdfrac%7B%5Csqrt3%7D%7B2%7D)
