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sleet_krkn [62]
3 years ago
8

Weather forecasts are based on a weather forecaster's judgment on which one of a number of scenarios is likely to happen. Each s

cenario, in turn, is based on a prediction on what may happen in the future given conditions that almost always change in unexpected ways. Thus, it is difficult to trust weather forecasts.
Which of the following statements best expresses the main conclusion of the above argument?

1. Conditions almost always change in unexpected ways.

2. Weather forecasts are difficult to trust

3. Weather forecasts are based on a number of potential scenarios.
Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

2. Weather forecasts are difficult to trust

Step-by-step explanation:

Words like thus are preliminar to a conclusion, that is, we use words like thus when we are going to conclude something.

For Example:

The New Englard Patriots have won 6 Super Bowls. Thus, the New England Patriots are a good NFL franchise.

The conclusion is that the Patriots are a good NFL franchise.

In this problem, we have that:

Thus, it is difficult to trust weather forecasts.

The conclusion is:

2. Weather forecasts are difficult to trust

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3 0
2 years ago
In ΔQRS, the measure of ∠S=90°, the measure of ∠R=29°, and SQ = 5.8 feet. Find the length of RS to the nearest tenth of a foot.
taurus [48]

Answer:

10.5 ft

Step-by-step explanation:

In ΔQRS,

  • m∠S=90°
  • m∠R=29°,
  • SQ = 5.8 feet.

See the diagram below.

The triangle is a Right Triangle,

Using trigonometric ratios,

Tan R=\dfrac{|SQ|}{|RS|} \\Tan 29^\circ=\dfrac{5.8}{|RS|}\\$Cross multiply$\\|RS|XTan 29^\circ=5.8\\|RS|=\dfrac{5.8}{Tan 29^\circ}\\$=10.5 ft (to the nearest tenth of a foot)

7 0
3 years ago
PLEASE HELP ME!!!<br><br> I don't understand....<br> If possible, please explain!
goblinko [34]
What do you need help with? lol
7 0
3 years ago
Read 2 more answers
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi

Let us find first and second derivative for f(x)

f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in (0, \pi/2) U(\pi,3\pi/2)\\

and decreasing in (\pi/2, \pi)U(3\pi/2,2\pi)

x=\frac{\pi}{4}, \frac{3\pi}{4}

f"(\pi/4)

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = 2sin \pi/4+2cos \pi/4 =2\sqrt{2}

Minimum value = 2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}

c)

f"(x) =0 gives tanx =-1

x= 3\pi/4, 7\pi/4

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

3 0
3 years ago
What’s the value of this expression?
yaroslaw [1]

Answer:

ans is 0

Step-by-step explanation:

(3/5)0×-2

(3/5)^0

so the answer Is 0

8 0
3 years ago
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