Answer:
The second alternative is correct
Step-by-step explanation:
We have been given the expression;

The above expression can be re-written as;

On the other hand;
![y^{\frac{1}{3}}=\sqrt[3]{y}](https://tex.z-dn.net/?f=y%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7By%7D)
Therefore, we have;
![x^{9}\sqrt[3]{y}](https://tex.z-dn.net/?f=x%5E%7B9%7D%5Csqrt%5B3%5D%7By%7D)
What is the question itself?
There are two terms since 3x is a term, and 5 is a term.
The van is traveling about 55.9 miles per hour.
Answer:
0
Step-by-step explanation:
Anything times 0 is 0.