Answer:
m(t) = m₀ e⁻⁰•⁰¹⁵ᵗ
Half-Life = 46.21 years.
Step-by-step explanation:
Radioactive reactions always follow a first order reaction dynamic
Let the initial mass of radioactive substance be m₀ and the mass at any time be m
(dm/dt) = -Km (Minus sign because it's a rate of reduction)
The question provides K = 0.015 from the given differential equation
(dm/dt) = -0.015m
(dm/m) = -0.015dt
∫ (dm/m) = -0.015 ∫ dt
Solving the two sides as definite integrals by integrating the left hand side from m₀ to m and the Right hand side from 0 to t.
We obtain
In (m/m₀) = -0.015t
(m/m₀) = (e^(-0.015t))
m = m₀ e^(-0.015t)) = m₀ e⁻⁰•⁰¹⁵ᵗ
m(t) = m₀ e⁻⁰•⁰¹⁵ᵗ
At half life, m(t) = (m₀/2), t = T(1/2)
(m₀/2) = = m₀ e⁻⁰•⁰¹⁵ᵗ
e⁻⁰•⁰¹⁵ᵗ = (1/2)
In e⁻⁰•⁰¹⁵ᵗ = In (1/2)
-0.015t = - In 2
t = (In 2)/0.015
t = (0.693/0.015)
t = 46.21 years
Half life = T(1/2) = t = 46.21 years.
Hope this Helps!!!
Answer:
<h2>
D. Two</h2>
Step-by-step explanation:
Two common points of the graphs (two intersects) means two solutions.
Answer:
3 - (n - 1) = 1/2(3n - 4)
Step-by-step explanation:
We want to write three minus the difference of a number and one equals one-half of the difference of three times the same number and four as an equation.
Let the number be n.
The first part is: three minus the difference of a number and one:
3 - (n - 1)
The second part is: one-half of the difference of three times the same number and four:
1/2(3n - 4)
Now, let us equate the first and second parts:
3 - (n - 1) = 1/2(3n - 4)
PS: I really do not understand the options
1000 your welcome no problem
Divide 2 cakes by 2/3 serving:
2 / 2/3 = 2 x 3/2 = 6/2 = 3 servings.
