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olga55 [171]
3 years ago
8

Disregard the "!"

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:first give brainilst and i answer

Step-by-step explanation:

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If the sin 30° = , then the cos 60° = _____. 0, because the angles are complementary , because the angles are complementary , be
g100num [7]

Answer:

1 is the answer

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
2.Solve the following quadratic equations<br> i. 9x^2 - 1/16<br> ii. 2h^2 - 3h - 27
Juli2301 [7.4K]
i)~9x^2-\dfrac{1}{16}=0\iff9x^2=\dfrac{1}{16}\iff x^2=\dfrac{1}{9\cdot16}\iff \\\\x^2=\dfrac{1}{144}\iff x=\pm\sqrt{\dfrac{1}{144}}=\pm\dfrac{1}{12}\Longrightarrow\boxed{x=\pm\dfrac{1}{12}}


ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\&#10;\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}

4 0
3 years ago
What is the standard form for this equation 6x=y+3
leva [86]

6x-y=3 this is the equation in standard form


8 0
3 years ago
Read 2 more answers
A 18 foot ladder is leaning against a wall as shown
Inga [223]
I'm guessing the diagram shows a ladder leaning against a wall, making a right angle triangle with respect to the ground and the wall.

So, the wall's height is going to be the 'h', which will also be the 'opposite side' from the angle <span>ϴ which is made from the ladder and the ground.
</span>The ladder's length (18 foot) is going to be the 'hypotenuse' side and the other remaining side will be the 'adjacent'.

Now, once you've sorted out which side is which, we have to find the h (opp), and according to  SOH CAH TOA, we will choose Sin<span>ϴ = opp/hyp.
</span>so Sinϴ = h/18....now we gotta find h, so 'cross multiply' the equation to get  h = 18 x sin<span>ϴ.
</span>
To find angle ϴ, simply take the inverse of Sinϴ= h/18... and you'll get ϴ =  sin-1 (sin inverse) h/18

Hope this helps



6 0
3 years ago
a card is chosen from a standard deck, then a month of the year is chosen. find the probability of getting a face card and june​
Irina-Kira [14]

Answer:

Probability of chossing a face card and the month of june = 0.019

Step-by-step explanation:

Let A be the event that a face card is chosen from a deck of 52 cards

And

B be the event that a month is being chosen from 12 months of an year

So,

n(S)for A=52

n(S)for B=12

As a deck of card has total of 12 face cards so

P(A)=12/52

=3/13

P(B)=1/12

As both the events are independent, the probability of A and B is the product of both events’ probabilities.

P(A and B)= P(A)*P(B)

=3/13*1/12

=3/156

=0.019

4 0
3 years ago
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