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2 years ago

Let f(x)=x^4-3x^3+5x-3, f(-2)

Mathematics

1 answer:

BabaBlast [244]2 years ago

8 0

$f(-2)=(-2)^4-3(-2)^3+5(-2)-3
\\f(-2)= 16+24-10-3\\
f(-2)=30-10-3\\
f(-2)=17$

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A meteorologist reports that the ration of snowfall in January to total snowfall during the average winter is 2 to 5. If 34 inch

Zepler [3.9K]

Answer:

13.6 inches.

Step-by-step explanation:

First do 2/5 = x/34, then multiply 34 by 2 and you get 68, then 68 divided by 5 is 13.6!

Hope this helped!

4 0

3 years ago

Help plz I’m not good at this

Natalka [10]

Answer:

The correct answer is A. 1/8

Step-by-step explanation:

Let's solve (1/3 * 9/16) / 1 1/2 = x

(1/3 * 9/16) / 1 1/2 = x

9/48 / 1 1/2 = 9/48 * 2/3 = 18/144

18/144, we can simplify dividing by 18 at the numerator and the denominator, this way:

x = 18 ÷ 18/ 144 * 18 = 1/8

The correct answer is A. 1/8

4 0

3 years ago

A number increased by fifteen is nineteen. A number increased by fifteen is nineteen.

elixir [45]

Answer:

the number is 4

Step-by-step explanation:

we can write this as

x + 15 = 19

now we transpose

x= 19-15

x= 4

5 0

2 years ago

Find the measure of each acute angle.

Alona [7]

Answer:

(19x - 1)° = 56°

(13x - 5)° = 34°

Step-by-step explanation:

Property of the interior angles of a triangle:

Sum of interior angles of a triangle is 180°.

Therefore, sum of angles of the given right triangle will be,

(19x - 1)° + (13x - 5)° + 90° = 180°

32x - 6 + 90 = 180

32x = 96

x = 3

(19x - 1)° = 19×3 - 1 = 56°

(13x - 5)° = 13×3 - 5 = 34°

7 0

2 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

2 years ago