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patriot [66]
3 years ago
13

Let f(x)=x^4-3x^3+5x-3, f(-2)

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0
f(-2)=(-2)^4-3(-2)^3+5(-2)-3
\\f(-2)= 16+24-10-3\\
f(-2)=30-10-3\\
f(-2)=17
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Read 2 more answers
Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 A) Both are solutions B) Neither
Dahasolnce [82]

Answer:

D) Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

Lets check the first point (-1,9)

Put in x =-1 y =9

x+y =8

-1+9 = 8

8 =8

This works

x^2 + y = 10

(-1)^2 +9 =10

1+9 = 10

10 = 10

This works

Lets check the second point (-2,6)

Put in x =-2 y =6

x+y =8

-2+6 = 8

4=8

This  does not work

We can stop now.  (-2,6) cannot be a solution

7 0
3 years ago
4xi + 5yi^8+ 6xi^3 + 2yi^4
Ad libitum [116K]

Answer:

The correct answer is,

7y - 2ix

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3 years ago
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