Let f(x)=x^4-3x^3+5x-3, f(-2)

Mathematics

1 answer:

BabaBlast [244]3 years ago

8 0

$f(-2)=(-2)^4-3(-2)^3+5(-2)-3
\\f(-2)= 16+24-10-3\\
f(-2)=30-10-3\\
f(-2)=17$

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