You need to use this formula: ([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3) Now its just getting 'a' by itself. ([c] times [sinA])/([sinC])=[a] [c]=16 square root of 3 sinA=sin(60)=(square root of 3)/2 sinC=sin(90)=1
Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides. The final y is: 8 square root of 3 Final answer is C.
