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3 years ago

Combining like terms 2 + 3x - X=4x

Mathematics

2 answers:

ololo11 [35]3 years ago

8 0

Answer:

Hi there!

Your answer is:

x= 1

Step-by-step explanation:

Goal- get all X's on one side, and all whole numbers on the other

2+3x -x = 4x

First, combine like terms on each side of the equal sign

2+ 2x = 4x

Next, think about the additive inverse property. What, added to 2x, equals 0? 2x + (-2x) =0! So, we <u>subtract</u> 2x from both sides!

2= 4x-2x

Simplify

2= 2x

Divide both sides by the coefficient of x (in this case, 2)

2/2 = x

2/2 is equal to 1

1= x

Hope this helps!

alukav5142 [94]3 years ago

3 0

Answer:

x = 1

Step-by-step explanation:

Combining the x terms, we get

2 + 2x = 4x, or 2 = 2x.

Then, after we divide both sides by 2 to isolate x, we get x = 1

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Read 2 more answers

Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t

katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on $y=x$ line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

$(x,y)\rightarrow (y,x)$

Points on line EF

$(0,6) , (-5,-2)$

On reflection of this line on $y=x$ the new points we get for line JK are

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Points on line GH

$(-4,9),(-9,1)$

On reflection on y=x line the new points we get for line LM are

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Slope of line JK

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}$

Slope of line LM

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}$

For two line to be parallel, their slopes will be same.

$m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}$

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

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