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Xelga [282]
3 years ago
13

Please Help!!!!!!! Simplify (√5)(3√5).

Mathematics
1 answer:
kirill [66]3 years ago
7 0

The answer is 15

multiply 3sqrt(25)

3*5=15

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andrew-mc [135]
Question 1) x=4
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3 years ago
Read 2 more answers
The area of a rectangular playground is 16 square yards. The length of the playground is 4 times longer than
Alexxandr [17]

length = 8 yd and width = 2 yd

So, Option D is correct.  

Step-by-step explanation:

Area of rectangular playground = 16 square yards

Width of playground = w

Length of playground = l = 4w

We need to find length(l) and width(w)

The formula used is:

Area = Length * Width

Putting values:

Area = Length * Width\\16=4w*w\\16=4w^2\\w^2=\frac{16}{4}\\w^2=4\\Taking\,\,square\,\,root:\\\sqrt{w^2}=\sqrt{4}\\ w=\pm 2

Since width of rectangle is always positive, so we will take w = 2

So. Width = 2

Length = 4w = 4(2) = 8

Hence, length = 8 yd and width = 2 yd

So, Option D is correct.  

Keywords: Area of rectangle

Learn more about Area of rectangle at:

  • brainly.com/question/4054269
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  • brainly.com/question/6564657

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3 0
3 years ago
Find what % of 70 is 12​
marshall27 [118]

Answer:

Percentage Calculator: 12 is what percent of 70? = 17.14.

Step-by-step explanation:

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4 0
2 years ago
The sum of 17 and a number x is expand to 20 (Write an equation for the decription)
Rudiy27

So the sum of 17 and a number x means to add them on one side of the equals sign. The other side would be your 20.

17 + x = 20

3 0
3 years ago
Please help, I didn't learn this in class!
NemiM [27]
Solve the following system using elimination:
{-2 x + 2 y + 3 z = 0 | (equation 1)
{-2 x - y + z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x - 3 y - 2 z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y+0 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)


Divide equation 2 by 5:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:
{-(2 x) + 0 y+3 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
v0 x+0 y+z = 0 | (equation 3)


Subtract 3 × (equation 3) from equation 1:
{-(2 x)+0 y+0 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:
{x+0 y+0 z = 1 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1, y = 1, z = 0

7 0
3 years ago
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