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Basile [38]
3 years ago
8

#8 please help due in 15 minutes!! Find the distance

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

approximately 3.873

Step-by-step explanation:

your work was close however we use the distance formula here

Distance = sqrt (y2-y1) +(x2-x1)

the answer to that comes out to be 3.873

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X Cube - 5x Square - 2 x + 24​
Otrada [13]

Answer:

(x+2)(x-4)(x-3)

(x²-4x+2x-2)(x-3)

(x²-2x-2)(x-3)

=x³-5x²-2x+24

So the answer true

8 0
3 years ago
Find the value of -|-2 + 9|<br>A. 7<br>B. -11<br>C. -7​
nexus9112 [7]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

-(-2 + 9)  Equation/Question

Step 2

-(-2 + 9)  Simplify

-(-2 + 9)

Step 3

-(-2 + 9)  Solve by adding

-(7)

=-7

Answer

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6 0
2 years ago
Please help. I don't need a big explanation just a answer
stiv31 [10]
A answer of the explanation for the explanation is the answer
6 0
3 years ago
Using the graph, select an answer.
saul85 [17]

Answer:

there's no graph??

Step-by-step explanation:

6 0
3 years ago
A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are
IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5 percent of these are defective.

This means that p = 0.05

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

0.0025 = 0.25% probability that both are defective

4 0
2 years ago
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