find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
Answer:
The Proof for
△ABD ≅ △CBD is below
Step-by-step explanation:
Given:


AD = CD .........BD bisect AC
To Prove:
△ABD ≅ △CBD
Proof:
In ΔABD and ΔCBD
BD ≅ BD ....……….{Reflexive Property}
∠ADB ≅ ∠CDB …………..{Measure of each angle is 90°(
)}
AD ≅ CD ....……….{
}
ΔABD ≅ ΔCBD .......….{By Side-Angle-Side Congruence test} ...Proved
Answer:
B is your answer!
Step-by-step explanation:
Hope I helped:)
Factor
x(2x-1)=0
x = 1/2, 0
Im pretty sure that the answer it is A. 7
because if you subtract 2 from 7 you get 5