Question

What is the approximate value of log6(25)?

Answer 1

Using the equivalence:

log_b(x)=log_e(x)/log_e(b)

(use base 10 or any other base if more convenient)

log_6(25)=log_e(25)/log_e(6)
=3.218876.../1.791759...
=1.796489...  (approximately)

Answer 2

Answer:

$log_{6}(25)=1.796$

Step-by-step explanation:

We have to find the value of $log_{6}(25)$

$log_{6}(25)=\frac{log_{10}25}{log_{10}6}$

[Since $log_{b}a=\frac{log_{10}a}{log_{10}b}$]

$log_{6}(25)=\frac{1.39794}{0.77818}$

$log_{6}(25)=1.796$

Therefore, $log_{6}(25)=1.796$ will be the answer.