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Ne4ueva [31]
3 years ago
13

Answer the question above on the ixl tab, please.

Mathematics
1 answer:
kramer3 years ago
8 0

Answer:

<h2>The answer is 10</h2>

Step-by-step explanation:

The formula for finding the combination of two given positive numbers is given by

<h3>_{n}C _{r} =  \frac{n!}{(n - r)!r!}</h3>

Where n and r are positive numbers

From the question we have

5 C 3

<u>Simplify</u>

That's

<h3>\binom{5}{3}  =  \frac{5!}{(5 - 3)!3!}  =  \frac{120}{2! \times 3  !}  \\  =  \frac{120}{2 \times 6}  \\  =  \frac{120}{12}</h3>

We have the final answer as

<h3>10</h3>

Hope this helps you

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3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
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Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

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<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

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<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

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One of the ideas that you have explored in previous courses is how to describe a set of data.
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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

D quadrinomial

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