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2 years ago

Answer the question above on the ixl tab, please.

Mathematics

1 answer:

kramer2 years ago

8 0

Answer:

<h2>The answer is 10</h2>

Step-by-step explanation:

The formula for finding the combination of two given positive numbers is given by

Where n and r are positive numbers

From the question we have

5 C 3

<u>Simplify</u>

That's

<h3> $\binom{5}{3} = \frac{5!}{(5 - 3)!3!} = \frac{120}{2! \times 3 !} \\ = \frac{120}{2 \times 6} \\ = \frac{120}{12}$ </h3>

We have the final answer as

Hope this helps you

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Anybody know the answer??

Anastasy [175]

The first one. 1 machine= x 5 mach.=5x. Total time is thus 5x+2/3=1 3/4h. Simply find x by doing 105min-40min/5 and that is 13.

4 0

3 years ago

Please help me!!!!!

Bas_tet [7]

Answer: see proof below

<u>Step-by-step explanation:</u>

Use the Sum & Difference Identity: tan (A - B) = (tanA - tanB)/(1 + tanA tanB)

Use the Half-Angle Identity: tan (A/2) = (1 - cosA)/(sinA)

Use the Unit Circle to evaluate tan (π/4) = 1

Use Pythagorean Identity: cos²A + sin²A = 1

<u>Proof LHS → RHS</u>

$\text{Given:}\qquad \qquad \qquad\dfrac{2\tan\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)}{1+\tan^2\bigg(\dfrac{\pi}{4}-\dfrac{A}{2}\bigg)}$

$\text{Difference Identity:}\qquad \dfrac{2 \bigg( \frac{\tan\frac{\pi}{4}-\tan\frac{A}{2}}{1+\tan\frac{\pi}{4}\cdot \tan\frac{A}{2}}\bigg)}{1+ \bigg( \frac{\tan\frac{\pi}{4}-\tan\frac{A}{2}}{1+\tan\frac{\pi}{4}\cdot \tan\frac{A}{2}}\bigg)^2}$

$\text{Substitute:}\qquad \qquad \dfrac{2 \bigg( \frac{1-\tan\frac{A}{2}}{1+\tan\frac{A}{2}}\bigg)}{1+ \bigg( \frac{1-\tan\frac{A}{2}}{1+\tan\frac{A}{2}}\bigg)^2}$

$\text{Simplify:}\qquad \qquad \qquad \dfrac{1-\tan^2\frac{A}{2}}{1+\tan^2\frac{A}{2}}$

$\text{Half-Angle Identity:}\qquad \quad \dfrac{1-(\frac{1-\cos A}{\sin A})^2}{1+(\frac{1-\cos A}{\sin A})^2}$

$\text{Simplify:}\qquad \qquad \dfrac{\sin^2 A-1+2\cos A-\cos^2 A}{\sin^2 A+1-2\cos A+\cos^2 A}$

$\text{Pythagorean Identity:}\qquad \qquad \dfrac{1-\cos^2 A-1+2\cos A}{2-2\cos A}$

$\text{Simplify:}\qquad \qquad \qquad \dfrac{2\cos A-2\cos^2 A}{2(1-\cos A)}\\\\.\qquad \qquad \qquad \qquad =\dfrac{2\cos A(1-\cos A)}{2(1-\cos A)}$

= cos A

LHS = RHS: cos A = cos A $\checkmark$

4 0

3 years ago

The balance of an account after t years can be found using the expression 6000(1.02)^t where the initial balance was $6000. By w

adelina 88 [10]

Answer:

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Step-by-step explanation:

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2 years ago

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In-s [12.5K]

Answer:

the answer is C,2^6×3^3

Step-by-step explanation:

6^3×2^6/2^3

=6^3×2^6-^3

=6^3×2^3

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3 years ago

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KonstantinChe [14]

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3 years ago

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