A hotel swimming pool is made up of four semicircles and a square. Find the perimeter of the swimming pool. Round your answer to
1 answer:
Answer:
75.4yd
Step-by-step explanation:
Find the diagram attached
Perimeter of the figure = perimeter of the 4 semicircles
Perimeter of a semicircle = πd/2
d is the diameter of the semicircle = 12yd
Perimeter of a semicircle = 3.14(12)/2
Perimeter of a semicircle = 37.68/2
Perimeter of a semicircle = 18.94yd
Perimeter of the 4 semicircles = 4 * 18.94
Perimeter of the 4 semicircles = 75.36yd
Hence the perimeter of the swimming pool to nearest tenth is 75.4yd
You might be interested in
Answer:
a) h = 123/x^2
b) S = x^2 +492/x
c) x ≈ 6.27
d) S'' = 6; area is a minimum (Y)
e) Amin ≈ 117.78 m²
Step-by-step explanation:
a) The volume is given by ...
V = Bh
where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:
123 = x^2·h
h = 123/x^2
__
b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.
__
c) The derivative of the area with respect to x is ...
When this is zero, area is at an extreme.
__
d) The second derivative is ...
This is positive, so the value of x found represents a minimum of the area function.
__
e) The minimum area is ...
The minimum area of metal used is about 117.78 m².