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neonofarm [45]
2 years ago
11

Explain how would you find the square root of a number​

Mathematics
2 answers:
nirvana33 [79]2 years ago
7 0

Answer:

multiply

Step-by-step explanation:

i know this from 3rd grade

Salsk061 [2.6K]2 years ago
7 0

Answer:using division method

Step-by-step explanation:

Example is the square root of 144

144 divided by the less prime number till 144 can not be divided again

144÷2=72

72÷2=36

36÷2=18

18÷2=9

9÷3=3

3÷3=1

Then you group the prime numbers used

(2×2)×(2×2)×(3×3)

Then take one of the prime numbers form each group

2×2×3=12

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Translate into a equation. one subtracted from two times a number is -45.​
sleet_krkn [62]

Answer:

2x - 1 = -45.

Step-by-step explanation:

2x - 1 = -45 is the required equation.

x is the number.

3 0
3 years ago
HELP LOOK AT THE PHOTO
Amanda [17]

\bf{Hello!}

The answer is 140°

Because we can use exterior angle property here

<u>Exter</u><u>ior</u><u> </u><u>angl</u><u>e</u><u> property</u><u> </u><u>:</u> It states that exterior angle is the sum of two opposite interior angles

y = 120 + 20 = 140°

6 0
3 years ago
Read 2 more answers
The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

4 0
3 years ago
Match the equation with the step needed to solve it.
viva [34]
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8 0
3 years ago
What’s the distance formula
Whitepunk [10]

Step-by-step explanation:

\text{Let}\ A(x_1,\ y_1)\ \text{and}\ B(x_2,\ y_2).\ \text{Then the distance between}\ A\ \text{and}\ B\ \text{is:}\\\\|AB|=\sqrt{(x_2-x_1)^2+(y_2-y1)^2}\\\\Example:\\\\A(2,\ 5),\ B(-1,\ 1)\\\\|AB|=\sqrt{(-1-2)^2+(1-5)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

7 0
3 years ago
Read 2 more answers
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