Question

6 _[2/5 +{3 1/4 _(3/8+1/2)}] Solve it

Answer 1

6_2/5 + (3(1/4)_3/8 + 1/2

Answer 2

Answer:

Step-by-step explanation:

$6-[\frac{2}{5}+\{3\frac{1}{4}-(\frac{3}{8}+\frac{1}{2})\}]\\\\=6-[\frac{2}{5}+\{3\frac{1}{4}-(\frac{3}{8}+\frac{1*4}{2*4})\}]\\\\=6-[\frac{2}{5}+\{\frac{13}{4}-(\frac{3}{8}+\frac{4}{8})\}\\\\=6-[\frac{2}{5}+\{\frac{13*2}{4*2}-\frac{7}{8}\}]\\\\=6-[\frac{2}{5}+\{\frac{26}{8}-\frac{7}{8}\}]\\\\=6-[\frac{2}{5}+\frac{19}{8}]\\\\=6-[\frac{2*8}{5*8}+\frac{19*5}{8*5}]\\\\=6-[\frac{16}{40}+\frac{95}{40}]\\\\=6-\frac{111}{40}\\\\=\frac{6*40}{1*40}-\frac{111}{40}\\\\=\frac{240}{40}-\frac{111}{40}$

=129/40

= $3\frac{9}{40}$

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