Answer:
x = 3
y = 4
hey, I am not 100% sure of the certainty of my answers, I am using what I remember about that topic but I do not know if it is right or wrong, I hope I have helped you, I did what I could.
Step-by-step explanation:
-3x + 2y = 23
5x + 2y = -17
X solution:
(you cancel the y)
-3x = 23
5x = -17
(you combine all the values above with those below)
2x = 6
(solve the ecuation normaly)
x = 6/2 = 3
Y solution:
(you replace the x)
-3(3) + 2y = 23
5(3) + 2y = -17
-9 + 2y = 23
15 + 2y = -17
(you combine all the values above with those below)
6 + 4y = 6
(solve the ecuation normaly)
4y = 0
y = 4
(I do not really know if the answer here is 0 or 4 since when passing the 4 to divide it would be 0/4 and I do not understand very well how that is solved)
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
x=14.5
Step-by-step explanation:
2x+5+6x-1=120
Combine like terms (combine all of the variables and then combine all of the constants)
8x+4=120
subtract 4 on both sides
8x=116
Divide 8
x=14.5
Hope this helps!
